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Karo-lina-s [1.5K]
3 years ago
12

What is the pressure of 0.540 mol of an ideal gas at 35.5 L and 223 K? Use mc031-1.jpg and mc031-2.jpg.

Chemistry
2 answers:
Reil [10]3 years ago
8 0
28.2 kPa -----------
Orlov [11]3 years ago
7 0

Answer: The pressure of an ideal gas 0.278 atm.

Explanation:

Volume of the ideal gas ,V = 35.5 L

Pressure of an ideal gas,P = 0.138 atm

Temperature of an ideal gas = 223 K

Number of moles of an ideal gas = 0.540 mol

Ideal gas equation is given as:

PV=nRT

P=\frac{n}{V}\times RT=\frac{0.540 mol}{35.5 L}\times 0.0820 atm l/mol K\times 223 K

P = 0.278 atm

The pressure of an ideal gas 0.278 atm.

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V₂ = V₁ + V' where V' = volume of water added.

So, From C₁V₁ = C₂V₂

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= 1.75 mol/L × 0.5 L ÷ 8.61 mol/L

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0.5 L = 0.102 L + V'

V' = 0.5 L - 0.102 L

= 0.398 L

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So, we need to add 398 mL of water to the nitric solution.

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<h3>What is Entropy? </h3>

Entropy is defined as the randomness of the particle. It depends on temperature and pressure or number of particle per unit volume.

It is directly proportional to the temperature and pressure of the gas.

<h3>What is Standard Molar Entropy? </h3>

The standard molar entropy is defined as the entropy content of the one mole of pure substance at the standard state of temperature and pressure of interest.

The standard molar entropy is also defined as the total amount of entropy which 1 mole of the substance acquire, as it is brought from 0K to standard conditions of temperature and pressure.

The standard molar entropy depends on the molas mass of atom, molecules or compound.

SF₄(g) has lower standard molar entropy. Due to less complexity of this molecules.

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Thus, we concluded that the increasing order of standard molar entropy (S°) is as follow:

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learn more about standard molar entropy:

brainly.com/question/15908262

#SPJ4

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