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Karo-lina-s [1.5K]
3 years ago
12

What is the pressure of 0.540 mol of an ideal gas at 35.5 L and 223 K? Use mc031-1.jpg and mc031-2.jpg.

Chemistry
2 answers:
Reil [10]3 years ago
8 0
28.2 kPa -----------
Orlov [11]3 years ago
7 0

Answer: The pressure of an ideal gas 0.278 atm.

Explanation:

Volume of the ideal gas ,V = 35.5 L

Pressure of an ideal gas,P = 0.138 atm

Temperature of an ideal gas = 223 K

Number of moles of an ideal gas = 0.540 mol

Ideal gas equation is given as:

PV=nRT

P=\frac{n}{V}\times RT=\frac{0.540 mol}{35.5 L}\times 0.0820 atm l/mol K\times 223 K

P = 0.278 atm

The pressure of an ideal gas 0.278 atm.

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Calcular la presión final de un gas que inicialmente está a 21°C y 0,98 atm. Sabiendo que su temperatura aumenta a 37°C.
KatRina [158]

Answer:

1.03 atm

Explanation:

Primero <u>convertimos 21 °C y 37 °C a K</u>:

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  • 37 °C + 273.16 = 310.16 K

Una vez tenemos las temperaturas absolutas, podemos resolver este problema usando la<em> ley de Gay-Lussac</em>:

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