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Veronika [31]
4 years ago
9

Julia produces a 2 mA current by moving the south pole of a bar magnet into a solenoid. The solenoid contains 150 loops of wire.

Which change should Julia make to generate a larger current
Physics
2 answers:
Alla [95]4 years ago
5 0

Answer:

1) increasing the number of turns

2) increase the area of the loop

3) by moving the magnet faster

Explanation:

As we know by the Faraday's law that rate of change in magnetic flux linked with the coil will induce EMF

so here we can say that magnetic flux is given as

\phi = NBA

now the induced EMF is given as

EMF = \frac{d\phi}{dt}

EMF = \frac{d(NBA)}{dt}

EMF = NA\frac{dB}{dt}

so in order to increase the current we need to increase the EMF

so we can increase it by

1) increasing the number of turns

2) increase the area of the loop

3) by moving the magnet faster

Alexus [3.1K]4 years ago
3 0
Using more loops of wire in the coil
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A small sphere with mass 1.5g hangs by a thread between two parallel vertical plates 5cm apart. The plates are insulating and ha
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The tralational equilibrium condition allows finding that the electric potential is   V = 4.8 10¹¹ V

Given parameter

  • The mass m = 1.5 g = 1.15 10-3 kg
  • The charge on the sphere q = 8.9 10-16 C
  • Plate spacing d = 5 cm = 5.00 10-2 m

To find

  • The potential difference

Newton's second law states that the force is proportional to the mass and the acceleration of the bodies, in the special case that the acceleration is zero, it establishes the condition for the equilibrium of the bodies

          ∑ F = 0

Where the bold indicate vector and F is the force

To use this equation we must fix a reference system with respect to which to carry out the decomposition and measurements of the forces; let's fix a system with the horizontal x axis and the vertical y axis, in the attachment I could see a free body diagram.

x- axis

     Fe - Tₓ = 0

     Fe = Tₓ

y-axis

     T_y - W = 0

     W = T_y

     mg = T_y

The electric force is

      Fe = q E = q V / d

let's use trigonometry to decompose the stress

     cos 30 =  T_y / T

     sin 30 = Tₓ / T

      T_y = T cos 30

      Tₓ = T sin 30

We substitute

        q V / d = T sin 30

        mg = T cos 30

It's solve the system of equations

         \frac{q \ V}{d \ m g} = tan 30

         V = \frac{d \ mg }{ q}\ tan \  30

It's calculate

         V = \frac{5.00 \ 10^{-2} 1.5 \ 10^{-3} \ 9.8}{ 8.9 10^{-16} } \ tan \ 30

         V = 4.768 10¹¹ V

In conclusion, using the equilibrium condition, we could find that the electric potential is V = 4.8 10¹¹ V

Learn more about equilibrium condition here:

brainly.com/question/1967702

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3 years ago
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