1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Neporo4naja [7]
3 years ago
14

In this type of bond, electrons are lost or gained by atoms, and the atoms are held together by electrical attraction.

Physics
1 answer:
expeople1 [14]3 years ago
8 0
<span>In Ionic type of bonding, electrons are lost (more protons than electrons and positive charge) or gained (more electrons than protons, still a negative charge) by atoms, and the atoms are held together by electrical attraction in the process. Covalent bondings are the sharing of electrons as well as partial bondings. Covalent bondings’ electrons have the same charges thus, there is no gaining or losing electrons in the process of sharing. Strong bondings are applicable only to Hydrogen (H) atoms. </span>
You might be interested in
A bear fells from 10m long grass <br> From where the bear is
Elina [12.6K]
He from the 10m long grass
3 0
2 years ago
A crate of mass 50kg is pushed along a floor with a force of 20N for a distance of
PSYCHO15rus [73]

Answer:

F=50kg

D=5m

W=FD

therefore work done is 250Nm

8 0
2 years ago
Calculate the total displacement of a mouse walking along a ruler, if it begins at the x=5cm, and then does the following: It wa
Lana71 [14]
<span>To begin, the mouse walks from 5 to 12 cm, for a displacement of 7 cm. Next, it walks 8 cm in the opposite direction, for a total displacement of (7 + [-8]) or (-1) cm. This leaves the mouse on 4 cm, and then it walks from there to the 7cm location, for a displacement of 7-4 or +3 cm. Adding 3cm to -1cm gives a final displacement of +2cm.</span>
6 0
3 years ago
A spring with a spring constant value of 2500 StartFraction N over m EndFraction is compressed 32 cm. A 1.5-kg rock is placed on
Sedaia [141]

Answer:

it's 9m

Explanation:

5 0
2 years ago
Read 2 more answers
Which method will correctly determine whether the forces on an object are balanced or unbalanced?
MaRussiya [10]

For this case, the first thing you should do is define a reference system.

Once the system is defined, we must follow the following steps:

1) Do the sum of forces in a horizontal direction

2) Do the sum of forces in vertical direction

The forces will be balanced if for each direction the net force is equal to zero.

The forces will be unbalanced if for each direction the net force is nonzero.

Answer:

Add the forces in the horizontal and vertical directions separately.

6 0
3 years ago
Read 2 more answers
Other questions:
  • A complete description of simple harmonic motion must take into account several physical quantities and various mathematical rel
    12·2 answers
  • If the bus driver is the last one off the bus then who closes the door?
    8·2 answers
  • Exercise 2.4.5: Suppose we add possible friction to Exercise 2.4.4. Further, suppose you do not know the spring constant, but yo
    10·1 answer
  • A singly charged ion (q=−1.6×10−19) makes 7.0 rev in a 45 mT magnetic field in 1.29 ms. The mass of the ion in kg is
    10·1 answer
  • If a roller coaster cart needs more Kinetic Energy to reach the top of the track, what are two ways to increase the amount of Ki
    15·1 answer
  • 2. A block of mass 1.2 kg lies on a frictionless surface. A man slides the block
    14·1 answer
  • The photograph shows a kettle made of the element copper. Which statement describes a chemical property of copper?
    13·2 answers
  • A student designs an experiment where he takes a small wood car with 1.0 inch diameter wheels and rolls it down a ramp. The stud
    11·1 answer
  • What observational evidence suggests that supermassive black holes are located at the centers of many galaxies
    5·1 answer
  • What is the algebraic expression for the component of the normal force in the vertical direction?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!