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meriva
3 years ago
10

It takes 500 J of work to compress a spring 10 cm. What is the force constant of the spring? (b) When a 3.0 kg block is pushed a

gainst a massless spring of force constant 4.5. 10' N/m, the spring is compressed 8.0 cm. The block is released and it slides 2.0 m from the point at which it is released across a horizontal surface before friction stops it. What is the coefficient of kinetic friction between the block and the surface?
Physics
1 answer:
NARA [144]3 years ago
8 0

Answer:

Explanation:

a) Energy stored in spring = 1/2 k x² = .5 x k 0.1²

500 = 5 x 10⁻³ k ,

k = (500/5) x 10³ = 10⁵ N/m

b )

k = 4.5 x 10¹ = 45 N/m

Stored energy = 1/2 k x² = .5 x 45 x 8² x 10⁻⁴ =1440 x 10⁻⁴ J

This energy gets dissipated by friction .

work done by friction = μ mg d

d is the distance traveled under friction

so 1440 x 10⁻⁴ = μ x 3 x 9.8 x 2

μ = 245 x 10⁻⁴  or 0.00245 which appears to be very small. .

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Please help fill in the blank Earth’s axis passes through the (blank) and south poles.
LuckyWell [14K]

Answer:

North

Explanation:

Have a nice day :)

7 0
3 years ago
Represent 0.783 kg with Sl units having an appropriate prefix Express your answer to three significant figures and include the a
zysi [14]

Answer:

783 grams

Explanation:

Here mass is given in kg

Some of the prefixes of the SI units are

1 gram = 10⁻³ kilogram

1 milligram = 10⁻⁶ kilogram

1 microgram = 10⁻⁹ kilogram

1 nanogram = 10⁻¹² kilogram

The number is 0.783

Here, the only solution where the number of significant figures is three is gram. If any other prefix is chosen then the significant figures will increase

1\ kilogram = 1000\ gram

\\\Rightarrow 0.783\ kilogram=0.783\times 1000\ gram\\ =783\ gram

So, 0.783 kg = 783 grams

5 0
3 years ago
Two ice skaters, Paula and Ricardo, initially at rest, push off from each other. Ricardo weighs more than Paula.
sveta [45]

Answer:

the two ice skater have the same momentum but the are in different directions.

Paula will have a greater speed than Ricardo after the push-off.

Explanation:

Given that:

Two ice skaters, Paula and Ricardo, initially at rest, push off from each other. Ricardo weighs more than Paula.

A. Which skater, if either, has the greater momentum after the push-off? Explain.

The law of conservation of can be applied here in order to determine the skater that possess a greater momentum after the push -off

The law of conservation of momentum states that the total momentum of two  or more objects acting upon one another will not change, provided there are no external forces acting on them.

So if two objects in motion collide, their total momentum before the collision will be the same as the total momentum after the collision.

Momentum is the product of mass and velocity.

SO, from the information given:

Let represent the mass of Paula with m_{Pa} and its initial velocity with u_{Pa}

Let represent the mass of Ricardo with m_{Ri} and its initial velocity with u_{Ri}

At rest ;

their velocities will be zero, i.e

u_{Pa} = u_{Ri} = 0

The initial momentum for this process can be represented as :

m_{Pa}u_{Pa} +  m_{Ri}u_{Ri} = 0

after push off from each other then their final velocity will be v_{Pa} and v_{Ri}

The we can say their final momentum is:

m_{Pa}v_{Pa} +   m_{Ri}v_{Ri} = 0

Using the law of conservation of momentum as states earlier.

Initial momentum = final momentum = 0

m_{Pa}u_{Pa} +  m_{Ri}u_{Ri} =  m_{Pa}v_{Pa} +   m_{Ri}v_{Ri}

Since the initial velocities are stating at rest then ; u = 0

m_{Pa}(0) + m_{Pa}(0) = m_{Pa}v_{Pa} +   m_{Ri}v_{Ri}

m_{Pa}v_{Pa} +   m_{Ri}v_{Ri}  = 0

m_{Pa}v_{Pa} = - m_{Ri}v_{Ri}

Hence, we can conclude that the two ice skater have the same momentum but the are in different directions.

 B. Which skater, if either, has the greater speed after the push-off? Explain.

Given that Ricardo weighs more than Paula

So m_{Ri} > m_{Pa} ;

Then \mathsf{\dfrac{{m_{Ri}}}{m_{Pa} }= 1}

The magnitude of their momentum which is a product of mass and velocity can now be expressed as:

m_{Pa}v_{Pa} =  m_{Ri}v_{Ri}

The ratio is

\dfrac{v_{Pa}}{v_{Ri}} =\dfrac{m_{Ri}}{m_{Pa}} = 1

v_{Pa} >v_{Ri}

Therefore, Paula will have a greater speed than Ricardo after the push-off.

6 0
3 years ago
the atomic weight of antimony is 121.76 amu. two naturally occurring isotopes of antimony. 121-Sb has an isotopic mass of 120.90
liubo4ka [24]
Isotope has 57.40% abundance
the other one 100% - 57.40% = 42.60%

mass of 121 (% abundance) + mass of 123 (% abundance) =  total mass (atomic weight)
(120.9038 amu)(0.5740) + (x amu)(0.426) = 121.76 amu
x = 122.9136

hope this help
6 0
3 years ago
A boat can travel 1010 miles against a current in the same time that it can travel 110110 miles with the current. The rate of th
Marizza181 [45]

Answer:

56.02 mph

Explanation:

Let the velocity of boat in still water is, v

Given that velocity of the current is 55 mph

Now, velocity against current is, v-55

velocity along the current is v+55.

And according to question, time taken by boat to travel 1010 miles against the current is equivalent to time take to travel 110110 miles with the current.

Therefore,

Time taken against the current is, t=\frac{1010}{v-55}

Time taken with the current is, t=\frac{110110}{v+55}

Now this time is equal.

Therefore,

\frac{1010}{v-55}=\frac{110110}{v+55}\\\frac{{v+55}}{{v-55}} =109.02\\v+55=109.02(v-55)\\v=56.02mph

Therefore, this is the velocity in still water.

3 0
3 years ago
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