55 Kg has a weight of 55x9.8= 539 N
That is equal to the Normal force.
The static friction = 0.19 x 539 = 102.4 N
Answer:
1.81 x 10^-4 m/s
Explanation:
M = 98700 kg
m = 780 kg
d = 201 m
Let the speed of second asteroid is v.
The gravitational force between the two asteroids is balanced by the centripetal force on the second asteroid.


Where, G be the universal gravitational constant.
G = 6.67 x 10^-11 Nm^2/kg^2

v = 1.81 x 10^-4 m/s
Simply draw the vector with the given coordinates.