Answer:
(a) The height of the cliff is 19.6 m
(b) The horizontal distance travelled by the ball is 60 m
Explanation:
Given;
initial horizontal velocity of the ball, u = 30 m/s
initial vertical velocity of the ball, v = 0
time taken for the ball to hit the ground, t = 2 s
(a) height of the cliff
h = vt + ¹/₂gt²
h = 0 + ¹/₂gt²
h = ¹/₂gt²
h = ¹/₂(9.8)(2)²
h = 19.6 m
(b) horizontal distance traveled by the ball = Range
Range = ut
Range = 30 (2)
Range = 60 m
To solve this problem we will apply the relation of Ohm's law, at the same time we will use the concept of resistance in a cable, resistivity and potential difference.
According to Ohm's law we have to
Here,
V = Voltage
I = Current
R = Resistance
At the same time resistance can be described as
Here,
= Resistivity of the material
l = Length of the specimen
A = Cross-sectional area
From the above expression we can write the current as,
Replacing we have that,
Therefore the current in the wire is 3.809A
<em>Note: The value obtained for the resistivity of Tungsten was theoretically obtained and can be consulted online.</em>
Because it’s a scientific method so it’s a scientific method
d=18cm=0.18m thickness of board
vi=420m/s speed before entering the board
vf=320m/s speed when leaving the board
vf²=vi²+2×a×d
Acceleration a=(vf²-vi²)/2/d
a=-205.5m/s².
As expected, a is negative because the bullet is decelerated.
vf=vi+a×t
t=(vf-vi)/a=(320-420)/(-205.5)= 100/205.5=0.486s
t=0.486s=486ms
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