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lorasvet [3.4K]
3 years ago
11

the density of dry air at 20 degrees celsius is 1.20 g/L. What is the mass of air, in kilograms, of a room that measures 24.0m b

y 15.0 m by 4.0 m?
Physics
1 answer:
horsena [70]3 years ago
8 0
<h2>Mass of air in a room that measures 24.0 m by 15.0 m by 4.0 m is 1728 kg.</h2>

Explanation:

Density of air = 1.20 g/L = \frac{1.20\times 10^{-3}kg}{10^{-3}m^3}=1.2kg/m^3

Size of room is 24.0m by 15.0 m by 4.0 m

Volume of room = 24 x 15 x 4 = 1440 m³

We know the equation

            Mass = Volume x Density

            Mass = 1440 x 1.2

            Mass = 1728 kg  

Mass of air in a room that measures 24.0 m by 15.0 m by 4.0 m is 1728 kg.

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Simora [160]

The correct answer for  the volume v of the solid obtained by rotating the region bounded by the given curves about the specified line. y = x2, y = 4x is 128/3 * π.

Volume of Solid of Revolution by Shell method is given by

V = 2π * integrate x(height) dx Here, height = 4x-x2

(1)& x-varies from x = 0 to x = 4 then from eqn(1)  V = 2π * integrate x(4x - x ^ 2) dx from x = 0 to 4 = 2π * integrate (4x ^ 2 - x ^ 3) dx from x = 0 to 4

Basic Rule(1) ∫ x^n dx =x^ n+1/ n+1

V=2 π [4((x ^ 3)/3) - (x ^ 4)/4] 0 ^ 4 =2 π[ 4/3 x^ 3 - x^ 4/4 ] 0 ^ 4

V = 2π [4/3 * 4 ^ 3 - (4 ^ 4)/4} - 0]

V = 128/3 * π.

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4 0
2 years ago
A 4.2 kg parachutist is moving straight downward with a speed of 3.85 m/s
statuscvo [17]
Kinetic energy= .5 x m x v^2
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4 0
3 years ago
An automobile rounds a curve of radius 50.0 m on a flat road.
bixtya [17]

Answer:

14m/s

Explanation:

Given parameters:

Radius of the curve  = 50m

Centripetal acceleration  = 3.92m/s²

Unknown:

Speed needed to keep the car on the curve = ?

Solution:

The centripetal acceleration is the inwardly directly acceleration needed to keep a body along a curved path.

 It is given as;

      a = \frac{v^{2} }{r}  

a is the centripetal acceleration

v is the speed

r is the radius

  Now insert the parameters and find v;

         v²   = ar

        v² = 3.92 x 50  = 196

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6 0
3 years ago
A marble rolls 269cm across the floor with a constant speed of in 44.1cm/s.
Marrrta [24]

Answer:

t = 6.09 seconds

Explanation:

Given that,

Speed, v = 44.1 cm/s

Distance, d = 269 cm

We need to find the time interval of the marble. Speed is distance per unit time.

v=\dfrac{d}{t}\\\\\implies t=\dfrac{d}{v}\\\\t=\dfrac{269\ \text{cm}}{44.1\ \text{cm/s}}\\\\t=6.09\ s

Hence, the time interval of the marble is 6.09 seconds.

6 0
3 years ago
The charges are in a uniform electric field whose direction makes an angle 36.8 ∘ with the line connecting the charges. What is
astraxan [27]

Complete question:

Point charges q1=- 4.10nC and q2=+ 4.10nC are separated by a distance of 3.60mm , forming an electric dipole. The charges are in a uniform electric field whose direction makes an angle 36.8 ∘ with the line connecting the charges. What is the magnitude of this field if the torque exerted on the dipole has magnitude 7.30×10−9 N⋅m ? Express your answer in newtons per coulomb to three significant figures.

Answer:

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Explanation:

Given;

The torque exerted on the dipole, T = 7.3 x 10⁻⁹ N.m

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E is the magnitude of the electric field

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First, we determine the magnitude dipole moment;

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Finally, we determine the magnitude of this field;

E = \frac{T}{P*sin(\theta)}=  \frac{7.3 X 10^{-9}}{1.476X10^{-11}*sin(36.8)}\\\\E = 825.6 N/C

E = 826 N/C (in three significant figures)

Therefore, the magnitude of this field is 826 N/C

6 0
3 years ago
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