A 10.00 kg block is placed at the top of a long frictionless inclined plane angled at 37.9 degrees relative to the horizontal. T
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Complete Question
A small metal sphere, carrying a net charge q1=−2μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q2= -8μC and mass 1.50g, is projected toward q1. When the two spheres are 0.80m apart, q2 is moving toward q1 with speed 20ms−1. Assume that the two spheres can be treated as point charges. You can ignore the force of gravity.The speed of q2 when the spheres are 0.400m apart is.
Answer:
The value
Explanation:
From the question we are told that
The charge on the first sphere is
The charge on the second sphere is
The mass of the second charge is
The distance apart is
The speed of the second sphere is
Generally the total energy possessed by when and
are separated by
is mathematically represented
Here KE is the kinetic energy which is mathematically represented as
substituting value
And U is the potential energy which is mathematically represented as
substituting values
So
Generally the total energy possessed by when and
are separated by
is mathematically represented
Here is the kinetic energy which is mathematically represented as
substituting value
And is the potential energy which is mathematically represented as
substituting values
From the law of energy conservation
So
Answer:
Δ KE = 249158.6 kJ
Explanation:
given data
Truck mass M = 1560 Kg
Truck initial speed, u = 28 m/s
mass of car m = 1070 Kg
initial speed of car u1 = 0 m/s
solution
first we get here final speed by using conservation of momentum that is express as
Mu = (M+m) V .......................1
put here value we get
1560 × 28 = (1560 + 1070 ) V
solve it we get
final speed V = 16.60 m/s
and
Change in kinetic energy will be here
Δ KE = .................2
put here value and we get
Δ KE =
solve it we get
Δ KE = 249158.6 kJ