Dimensional formula of current density
2 answers:
<em>The Dimensional Formula is ![[M ^{-2} A]](https://tex.z-dn.net/?f=%5BM%20%5E%7B-2%7D%20A%5D)
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When we are talking about current density, we are referring to "Ampere per unit area", so the unit we would use is
Thank you for your question! I hope this helped! Have an amazing rest of your week and feel free to let me know if you need any further help with anything! :D
When we are talking about current density, we are referring to "Ampere per unit area", so the unit we would use is
Thank you for your question! I hope this helped! Have an amazing rest of your week and feel free to let me know if you need any further help with anything! :D
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- There are two magnetic and geographic poles each, north and south
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- The magnetic north and south poles are not the same as the geographic north and south poles
- In a compass, the needle points to the magnetic north pole
- By convention, the magnetic north pole corresponds to the geographic south pole
- The magnetic south pole corresponds to the geographic north pole
- The magnetic field lines of a magnet start from the magnetic north pole and end at the magnetic south pole
The magnetic north pole of the earth's magnet is the geographic south pole.
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#SPJ10
a) 0.0028 rad/s
b)
c)
Explanation:
a)
When an object is in circular motion, the angular speed of the object is the rate of change of its angular position. In formula, it is given by
where
is the angular displacement
t is the time interval
The angular speed of an object in circular motion can also be written as
(1)
where
v is the linear speed of the object
r is the radius of the orbit
For the spaceship in this problem we have:
is the linear speed, converted into m/s,
is the radius of the orbit
Subsituting into eq(1), we find the angular speed of the spaceship:
b)
When an object is in circular motion, its direction is constantly changing, therefore the object is accelerating; in particular, there is a component of the acceleration acting towards the centre of the orbit: this is called centripetal acceleration, or radial acceleration.
The magnitude of the radial acceleration is given by
where
is the angular speed
is the radius of the orbit
For the spaceship in the problem, we have
is the angular speed
is the radius of the orbit
Substittuing into the equation above, we find the radial acceleration:
c)
When an object is in circular motion, it can also have a component of the acceleration in the direction tangential to its motion: this component is called tangential acceleration.
The tangential acceleration is given by
where
is the change in the linear speed
is the time interval
In this problem, the spaceship is moving with constant linear speed equal to
Therefore, its linear speed is not changing, so the change in linear speed is zero:
And therefore, the tangential acceleration is zero as well: