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Svetllana [295]
3 years ago
8

A particle of mass m=375 g is launched with velocity of A =4 moves with a length AB=2.5m under the action of tractive force F=3.

46 N making an angle 30. during its motion between A and B which is subjected to a frictional force f=1.5 N
calculate V of B by applying the kinetic energy theorem​
Physics
1 answer:
DiKsa [7]3 years ago
3 0

Answer:

The final speed is 5.78 m/s.

Explanation:

mass, m = 375 g = 0.375 kg

initial velocity, u = 4 m/s

Distance, s = 2.5 m

Angle, A = 30 degree

Force, F = 1.5 N

let the final velocity is v.

Use the work energy theorem

Work done = change in kinetic energy

W= 0.5 m(v^2 - u^2)\\\\F s cos A= 0.5 m (v^2 - u^2)\\\\1.5\times 2.5\times cos30= 0.5\times 0.375\times (v^2 - 16)\\\\v = 5.78 m/s

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Answer:

See answers below

Explanation:

a.

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b.

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3 years ago
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Answer:

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Explanation:

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From the given information we make the following summary

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The distance by the first balloon is

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Inputting the values

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The distance traveled by the second balloon

D = u_{2} t_{2}  + \frac{1}{2} at_{2}^2

Inputting the values

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simplifying

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Substituting D of the first balloon into the D of the second balloon and solving

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Now we know the value of t. We input this into the equation of the first balloon the to get height of the apartment

D = 4.9(3.3)^2\\ D = 53.361 m

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Answer:

brainly.com/question/11872573

Explanation:

all the credit goes to the user who answered this.

I do not have any rights on this.

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