Answer:
The phenomenon known as "tunneling" is one of the best-known predictions of quantum physics, because it so dramatically confounds our classical intuition for how objects ought to behave. If you create a narrow region of space that a particle would have to have a relatively high energy to enter, classical reasoning tells us that low-energy particles heading toward that region should reflect off the boundary with 100% probability. Instead, there is a tiny chance of finding those particles on the far side of the region, with no loss of energy. It's as if they simply evaded the "barrier" region by making a "tunnel" through it.
Explanation:
Answer:
moon disappear because of the rotation
This is what wiki says hope it helps
A displacement is a vector whose length is the shortest distance from the initial to the final position of a point P.[1] It quantifies both the distance and direction of an imaginary motion along a straight line from the initial position to the final position of the point.
A displacement may be also described as a 'relative position': the final position of a point (Sf) relative to its initial position (Si), and a displacement vector can be mathematically defined as the difference between the final and initial position vectors:
★ A grey hound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but 3 leaps of the hound are equal to 5 leaps of the hare.
★ The speed of the hound and the hare
★ The speed of the hound and the hare = 25:18
As it's given that a grey hound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but 3 leaps of the hound are equal to 5 leaps of the hare.
So firstly let us assume a metres as the distance covered by the hare in one leap.
Ok now let's talk about 5 leaps,.! As it's cleared that the hare cover the distance of 5a metres.
But 3 leaps of the hound are equal to 5 leaps of the hare.
Henceforth, (5/3)a meters is the distance that is covered by the hound.
Now according to the question,
Hound pursues a hare and takes 5 leaps for every 6 leaps of the hare..! (Same interval)
Now the distance travelled by the hound in it's 5 leaps..!
Now the distance travelled by the hare in it's 6 leaps..!
Now let us compare the speed of the hound and the hare. Let us calculate them in the form of ratio..!
Answer:
1. Kinetic Energy = 0.0161 Joules
2. Height = 0.0137m
Explanation:
Given
Length of Rod, l = 0.64m
Mass, m = 120g = 0.12kg
Angular speed, w = 1.40 rad/s
a.
Calculating the Rod's kinetic energy
This is calculated by
Kinetic Energy = ½Iw²
Where I = rotational inertia of the rod about an axis.
This is calculated as follows;
I = Icm + mh²
I = ImL² + m(L/2)²
I = 1/12 * 0.12 * 0.64² + 0.12 * (0.64/2)²
I = 0.016384 kgm²
By substituton
KE = ½Iw² becomes
KE = ½ * 0.016384 * 1.40²
KE = 0.01605632J
KE = 0.0161 Joules
2. Using the total conservation of momentum;
K + U = Kf + V
Where K = Initial Kinetic Energy of the rod at lowest point.
U = Initial gravitational potential energy of the rod at lowest point
Kf = Final Kinetic Energy of the rod at maximum height = 0 J
V = Final gravitational potential energy of the rod at maximum height
So, K + U = Kf + V become
K + U = 0 + V
K + U = V
K = V - U = mgh
substitute 0.01605632J for K
0.01605632J = mgh
h = 0.01605632J/mg
h = 0.01605632J/(0.12 * 9.8)
h = 0.013653333333333
h = 0.0137m
