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lisabon 2012 [21]
4 years ago
12

You have been given a piece of evidence indicating that plant and animal life is scarce in this environment. Identify this envir

onment and the correct explanation.
Chemistry
1 answer:
vladimir2022 [97]4 years ago
5 0

Answer:

Desert.

Explanation:

Desert is a region that has low amount of precipitation or rainfall throughout the year. Desert is also characterized by the fact that desert has high evaporation rate because desert is very hot.

Not all plants and animals can thrive in this kind of condition, but few plants and animals can and they do that by developing an advance features or traits so as to survive the region. The most common example of plant that can thrive in the desert is the cactus plant and the most common example of animal that can thrive in the desert is the camel.

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It’s sulfur because it shows little reactivity.
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Determine the number of valence electrons in pcl₃ and then draw the corresponding lewis structure.
Nikolay [14]

The number of valence electrons in PCl_{5} will be 26.

The atom's outermost inhabited shell is where valence electrons are found. They are significant because they have a major impact on how an atom's chemical characteristics are determined.

The number of valence electron in P in 5 and number of valence electron in Cl is 7. There are one molecule of P and three molecule of Cl in  PCl_{5}  molecule. By adding all valence electrons , the total number of valance electrons will be 26.

The Lewis structure of  PCl_{5}  is shown as:

Therefore, the number of valence electrons in PCl_{5} will be 26.

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3 years ago
A student takes a measured volume of 3.00 M HCl to prepare a 50.0 mL sample of 1.80 M HCl. What volume of 3.00 M HCl did the stu
vlabodo [156]

Answer is 30.0mL

according to the question dilution is performed by the student which can be calculated with the help of :

                          M_{1}V_{1}=M_{2}V_{2}     EQUATION (1)


Here, we have:

 M_{1} = 3M

  V_{1}  = y mL

M_{2}= 1.80 M

V_{2} = 50.0mL

putting the known values in equation (1) which will give us value of V_{1}

                                         3.00× y =1.80 ×50.0

                                                         y= 30.0mL

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