3CaCl2 + 2AlF3 --> 3CaF2 + 2AlCl3

Chemistry

1 answer:

Tresset [83]2 years ago

5 0

Answer:

54 moles

Explanation:

The ratio of AIF3 to CaF2 is, as seen in the equation, 2:3. This means you multiply 36 moles by 3, and then divide it by 2. This equals 54 moles of CaF2.

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AlCl3 + Na NaCl + Al Did Cl change oxidation number?

gizmo_the_mogwai [7]

Yes. If this is the balanced equation:

AlCl3 + 3Na —— 3NaCl + Al

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6 0

3 years ago

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What is the molarity of solution obtained when 5.71 g of sodium carbonate-10-water is dissolved in water and made up to 250.0 cm

disa [49]

We have to know the molarity of solution obtained when 5.71 g of Na₂CO₃.10 H₂O is dissolved in water and made up to 250 cm³ solution.

The molarity of solution obtained when 5.71 g of sodium carbonate-10-water (Na₂CO₃.10 H₂O) is dissolved in water and made up to 250.0 cm^3 solutionis: (A) 0.08 mol dm⁻³

The molarit y of solution means the number of moles of solute present in one litre of solution. Here solute is Na₂CO₃.10 H₂O and solvent is water. Volume of solution is 250 cm³.

Molar mass of Na₂CO₃.10 H₂O is 286 grams which means mass of one mole of Na₂CO₃.10 H₂O is 286 grams.

5.71 grams of Na₂CO₃.10 H₂O is equal to $\frac{5.71}{286}$ = 0.0199 moles of Na₂CO₃.10 H₂O. So, 0.0199 moles of Na₂CO₃.10 H₂O present in 250 cm³ volume of solution.

Hence, number of moles of Na₂CO₃.10 H₂O present in one litre (equal to 1000 cm³) of solution is $\frac{0.0199 X 1000}{250}$ = 0.0796 moles. So, the molarity of the solution is 0.0796 mol/dm³ ≅ 0.08 mol/dm³