Answer:
Methods for determining or delivering precise volumes include volumetric pipets and pycnometers; less precise methods include burets, graduated cylinders, and graduated pipets. In this experiment, you will measure masses and volumes to determine density. Four different metal cylinders are investigated.
Explanation:
Answer:
a) 2.01 g
Explanation:
- Na₂CO₃ (s) + 2AgNO₃ (aq) → Ag₂CO₃ (s) + 2NaNO₃
First we <u>convert 0.0302 mol AgNO₃ to Na₂CO₃ moles</u>, in order to <em>calculate how many Na₂CO₃ moles reacted</em>:
- 0.0302 mol AgNO₃ *
= 0.0151 mol Na₂CO₃
So the remaining Na₂CO₃ moles are:
- 0.0340 - 0.0151 = 0.0189 moles Na₂CO₃
Finally we <u>convert Na₂CO₃ moles into grams</u>, using its <em>molar mass</em>:
- 0.0189 moles Na₂CO₃ * 106 g/mol = 2.003 g Na₂CO₃
The closest answer is option a).
Answer:
1.0 L
Explanation:
Given that:-
Mass of
= 
Molar mass of
= 64.099 g/mol
The formula for the calculation of moles is shown below:

Thus,


According to the given reaction:-

1 mole of
on reaction forms 1 mole of 
0.0396 mole of
on reaction forms 0.0396 mole of 
Moles of
= 0.0396 moles
Considering ideal gas equation as:-

where,
P = pressure of the gas = 742 mmHg
V = Volume of the gas = ?
T = Temperature of the gas = ![26^oC=[26+273]K=299K](https://tex.z-dn.net/?f=26%5EoC%3D%5B26%2B273%5DK%3D299K)
R = Gas constant = 
n = number of moles = 0.0396 moles
Putting values in above equation, we get:

<u>1.0 L of acetylene can be produced from 2.54 g
.</u>
Answer:
0.170 M
Explanation:
M1V1=M2V2
(25.0mL)(0.123M)=(18.04mL)(x)
x= 0.170 M
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