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garik1379 [7]
3 years ago
13

Using the formula for velocity shown below, what is the average velocity of a bicyclist who biked 20 miles north of where he beg

an for a duration of 4 hours?
Chemistry
1 answer:
Marat540 [252]3 years ago
3 0

8.1km/hr due North

Explanation:

Given parameters:

Displacement = 20 miles North

Time = 4hours

Unknown;

Velocity = ?

Solution:

Velocity is the speed in a particular direction. It is simply displacement divided by time. A change in position with time.

                Velocity = \frac{displacement}{time}

The unit is usually expressed in km/hr or m/s

We need to convert the given displacement to that in km:

              1 mile = 1.609km

             20miles = 1.609 x 20,   32.18km

Velocity  =   \frac{32.18}{4} = 8.1km/hr due North

Learn more:

Velocity brainly.com/question/10962624

#learnwithBrainly

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Si la eficiencia de una máquina de calor es del 50% significa que ?
Karolina [17]

Answer:

No toques el link

Explanation:

8 0
3 years ago
What devices will you use to measure the mass and the volume in this experiment? (density)
bekas [8.4K]

Answer:

Methods for determining or delivering precise volumes include volumetric pipets and pycnometers; less precise methods include burets, graduated cylinders, and graduated pipets. In this experiment, you will measure masses and volumes to determine density. Four different metal cylinders are investigated.

Explanation:

8 0
2 years ago
Sodium carbonate reacts with silver nitrate according to the following balanced equation: Na2CO3 (s) + 2 AgNO3 (aq) → Ag2CO3 (s)
klemol [59]

Answer:

a) 2.01 g

Explanation:

  • Na₂CO₃ (s) + 2AgNO₃ (aq) → Ag₂CO₃ (s) + 2NaNO₃

First we <u>convert 0.0302 mol AgNO₃ to Na₂CO₃ moles</u>, in order to <em>calculate how many Na₂CO₃ moles reacted</em>:

  • 0.0302 mol AgNO₃ * \frac{1molNa_2CO_3}{2molAgNO_3}  = 0.0151 mol Na₂CO₃

So the remaining Na₂CO₃ moles are:

  • 0.0340 - 0.0151 = 0.0189 moles Na₂CO₃

Finally we <u>convert Na₂CO₃ moles into grams</u>, using its <em>molar mass</em>:

  • 0.0189 moles Na₂CO₃ * 106 g/mol = 2.003 g Na₂CO₃

The closest answer is option a).

8 0
3 years ago
Acetylene gas, C2H2, can be produced by the reaction of calcium carbide and water. CaC2(s) + 2H2O(l) --&gt; C2H2(g) + Ca(OH)2(aq
nekit [7.7K]

Answer:

1.0 L

Explanation:

Given that:-

Mass of CaC_2 = 2.54\ g

Molar mass of CaC_2 = 64.099 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{2.54\ g}{64.099\ g/mol}

Moles_{CaC_2}= 0.0396\ mol

According to the given reaction:-

CaC_2_{(s)} + 2H_2O_{(l)}\rightarrow C_2H_2_{(g)} + Ca(OH)_2_{(aq)}

1 mole of CaC_2 on reaction forms 1 mole of C_2H_2

0.0396 mole of CaC_2 on reaction forms 0.0396 mole of C_2H_2

Moles of C_2H_2 = 0.0396 moles

Considering ideal gas equation as:-

PV=nRT

where,

P = pressure of the gas = 742 mmHg  

V = Volume of the gas = ?

T = Temperature of the gas = 26^oC=[26+273]K=299K

R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

n = number of moles = 0.0396 moles

Putting values in above equation, we get:

742mmHg\times V=0.0396 mole\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 299K\\\\V=\frac{0.0396\times 62.3637\times 299}{742}\ L=1.0\ L

<u>1.0 L of acetylene  can be produced from 2.54 g CaC_2.</u>

4 0
3 years ago
A 25.0 mL sample of 0.123 M HCl was titrated with 18.04 mL of NaOH . What is the concentration of the NaOH ?
Blababa [14]

Answer:

0.170 M

Explanation:

M1V1=M2V2

(25.0mL)(0.123M)=(18.04mL)(x)

x= 0.170 M

* Please text me at 561-400-5105 for tutoring: I can do assignments, labs, exams, etc. :)

5 0
3 years ago
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