Solution:
We have to use the Henderson-Hasselbalch equation: for this calculation
Henderson–Hasselbalch equation describes the derivation of pH as a measure of acidity by using pKa, the negative log of the acid dissociation constant in biological and chemical systems. The equation is also useful for estimating the pH of a buffer solution and finding the equilibrium pH in acid-base reaction.
The equation is given by:
Here, [HA] is the molar concentration of the un dissociated weak acid, [A⁻] is the molar concentration (molarity, M) of this acid's conjugate base and pKa is −log10 Ka where Ka is the acid dissociation constant, that is:
pH = pKa + log([A^-]/[HA])
We look up the pKa for acetic acid:
pKa = 4.76
Let x = molarity of AcO^- and y = molarity of AcOH: Then we have the following two equations in two unknowns:
(1) x + y = 0.10 M
and
(2) 4.9 = 4.76 + log(x/y)
Further calcite the value of x and y by algebraic method and get the answer.
Answer:
Red, orange, yellow, green, blue, indigo, violet.
Explanation:
Answer:
See below.
Step-by-step explanation:
The two isotopes are Cl-35 and Cl-37.
The average atomic mass (35.45 u) is closer to 35 u, so most of the atoms are Cl-35.
mass number = number of protons + number of neutrons
A = p + n
35 = 17 + n
n = 35 – 17
n = 18
∴ Most chlorine atoms contain 18 neutrons.
Answer: B. CH₂OH
Explanation:
First off, we need a liquid solvent. Eliminate C and D.
Now, we have to consider polarity.
- Carbon tetrachloride is nonpolar, so sodium chloride will be insoluble.
- CH₂OH is polar, so sodium chloride will be soluble.