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3 years ago

The sequence of 5,8,14,26

2 answers:

5 0

Okay so to get to 8 from 5, you add 3.

Now to get to 14 from 8, you add 6.

Lastly, to get to 26 from 14, you add 12.

Do you see the pattern in 3,6,12? You're just doubling. So, next in the sequence would be 50 because you would add 24 to 26 (because 12 x 2 = 24)

I hope this helps! :)

omeli [17]3 years ago

4 0

So are you like putting that in order or like you doin the whats next

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lisov135 [29]

Answer:

d. y=-1; x=7

Step-by-step explanation:

8 0

2 years ago

State if the two triangles are congruent. If they are, state how you know.

ankoles [38]

Answer:

Step-by-step explanation:

yes congruent, by AAS

the angles are stating , w/ the little red lines that they are the same.. so we know two angles of the triangles are the same, and we also know that one side touching is the same. so yes.. AAS.

6 0

3 years ago

Write the equation of a line perpendicular to y= -5/6x-3 and whose y-intercept is (0,11).

worty [1.4K]

Answer:

y=6/5x+11

Step-by-step explanation:

Perpendicular lines have the opposite sign and reciprocal of the original line. Since the y-intercept is 11 we know that it is 6/5x+11

8 0

3 years ago

Enter the simplified form of the complex fraction in the box. Assume no denominator equals zero.

Olenka [21]

Answer:

$\frac{(9-x)}{3x}$

Step-by-step explanation:

we have

$\frac{\frac{2}{x-3}-\frac{3}{x}}{\frac{3}{x-3}}$

step 1

Solve the numerator of the quotient

$\frac{2}{x-3}-\frac{3}{x}=\frac{2x-3(x-3)}{(x-3)x}=\frac{2x-3x+9}{(x-3)x}=\frac{9-x}{(x-3)x}$

step 2

substitute in the original expression

$\frac{\frac{9-x}{(x-3)x}}{\frac{3}{x-3}}$

$\frac{(x-3)(9-x)}{3x(x-3)}$

step 3

simplify

$\frac{(9-x)}{3x}$

5 0

3 years ago

1-3. Find the center point, the radius and the diameter for the following equation: x² + y2 = 16

kogti [31]

Answer:

Center: (0, 0)

Radius: 4

Step-by-step explanation:

Circle Standard Equation: (x - h)² + (y - k)² = r²

(h, k) is center

r is radius

We see that our <em>h</em> and our <em>k</em> are both 0.

∴ Our center is (0, 0), origin.

We see that our r² = 16

√r² = √16

∴ Our radius is equal to 4

3 0

3 years ago