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Shalnov [3]
3 years ago
6

The reckless risk taking found among many adolescents is most likely due to the effects of _______.

Physics
2 answers:
ivanzaharov [21]3 years ago
8 0
The reckless risk taking found among many adolescents is most likely due to the effects of        <span>Peer pressure</span>
alexdok [17]3 years ago
3 0
Oh that's nothing to worry about.  It's normal.  It's due to the effects of youth,
and the instinctive impression of immortality that comes with it at no extra
charge just pay shipping and handling. 

Adolescent reasoning goes something like this:  "Whaddaya mean
this is dangerous ?  Whaddaya mean I'm being reckless ? ! ?
Who says ?  I've been doing it for almost a week now and I haven't
died yet and I don't know anybody who died from it, so it can't be that bad,
and you don't know anything and you just don't want me to have any fun,
and I'm just gonna keep doing it at least until I need glasses."
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Goshia [24]

Answer:

i believe 222222222222222222222 mikeoclong

Explanation:

5 0
3 years ago
A 10 Kg dog is running with a speed of 5.0 m/s what is the minimum work required to stop the dog
ra1l [238]

Answer:

25J

Explanation:

Given parameters:

Mass of the dog  = 10kg

Speed of the dog  = 5m/s

Unknown:

The minimum energy required to stop the dog  = ?

Solution:

The dog is moving with a kinetic energy and to stop the dog, an equal amount of kinetic energy generated must be applied to the dog.

 To find the kinetic energy;

        K.E  = \frac{1}{2} m v²

m is the mass

v is the velocity

Now insert the parameters and solve;

      K.E  =  \frac{1}{2}  x 10 x 5  = 25J

8 0
3 years ago
A photographer uses his camera, whose lens has a 50 mm focal length, to focus on an object 2.5 m away. He then wants to take a p
Temka [501]

Answer:

0.004 m away from the film

Explanation:

u = Object distance

v = Image distance

f = Focal length = 50 mm

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{0.05}-\frac{1}{2.5}\\\Rightarrow \frac{1}{v}=\frac{98}{5} \\\Rightarrow v=\frac{5}{98}=0.051\ m

The image distance is 0.051 m

When u = 50 cm

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{0.05}-\frac{1}{0.5}\\\Rightarrow \frac{1}{v}=18\\\Rightarrow v=\frac{1}{18}=0.055\ m

The image distance is 0.055 m

The lens has moved 0.055-0.051 = 0.004 m away from the film

3 0
3 years ago
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krek1111 [17]

Answer:

Explanation:

The stunt will likely sustain serious injury in case of concrete blocks because the average force acting on the person will be more because concrete blocks do not squeeze to provide more time for the force to act on the body instead it acts for a small amount of interval.

Impulse=F_{avg}\times \Delta T

As impulse is constant so time requires to act force on the body is more as compared to concrete block and thus average force in mattress case is less.  

8 0
3 years ago
Suppose Earth's gravitational force were decreased by half. How would this change affect a game of basketball?
Damm [24]
It would make us lighter, and it would be easier to dunk the ball. The ball would also bounce higher.
Hopefully this helps!!!:)
4 0
3 years ago
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