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Shalnov [3]
3 years ago
6

The reckless risk taking found among many adolescents is most likely due to the effects of _______.

Physics
2 answers:
ivanzaharov [21]3 years ago
8 0
The reckless risk taking found among many adolescents is most likely due to the effects of        <span>Peer pressure</span>
alexdok [17]3 years ago
3 0
Oh that's nothing to worry about.  It's normal.  It's due to the effects of youth,
and the instinctive impression of immortality that comes with it at no extra
charge just pay shipping and handling. 

Adolescent reasoning goes something like this:  "Whaddaya mean
this is dangerous ?  Whaddaya mean I'm being reckless ? ! ?
Who says ?  I've been doing it for almost a week now and I haven't
died yet and I don't know anybody who died from it, so it can't be that bad,
and you don't know anything and you just don't want me to have any fun,
and I'm just gonna keep doing it at least until I need glasses."
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A car is driving at 30 m/s it has a mass of 1800 kg what is the cars momentum?
Ostrovityanka [42]

Answer:

Explanation:

Momentum is a concept and is defined as,

Momentum = mass × velocity

So to calculate the momentum of the car

momentum of the car = mass of the car × velocity of the car

So we get,

momentum of the car = 1800 × 30

= 54000 Ns

5 0
4 years ago
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Based on the data table,which car won the race?
kobusy [5.1K]

Answer:

car one

Explanation:

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3 years ago
How tall would a tower need to be if the period of a pendulum were 30. seconds
Virty [35]
We use the following expression

T = 2*pi *sqrt(l/g)

Where T is the period of the pendulum

l is the length of the pendulum

and g the acceleration of gravity

We solve for l

l = [T/2*pi]² *g = [30s/2*pi]²* 9.8 [m/s²] = 223.413 m

The tower would need to be at least 223.413 m high
4 0
3 years ago
A 75 W lightbulb is being run on a 110 V outlet. Determine the resistance of the lightbulb. Provide a detailed description of th
Sauron [17]
Power is defined as

P = I*V

where I is the current and V is the voltage

Ohm's law gives us the relation betwen Voltage and current in a resistive component

V = I*R ,  Then

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R = (110 V)²/ 75W =  161.33 ohms
8 0
3 years ago
You are trying to overhear a juicy conversation, but from your distance of 24.0m , it sounds like only an average whisper of 40.
Neporo4naja [7]

Answer:

The distance is r_2  =  0.24 \  m

Explanation:

From the question we are told that

       The  distance from the conversation is r_1    =  24.0 \ m

       The  intensity of  the sound at your position is  \beta _1 =  40 dB

        The  intensity at the sound at the new position is  \beta_2 =  80.0dB

Generally the intensity in  decibel is  is mathematically represented as

      \beta  =  10dB log_{10}[\frac{d}{d_o} ]

The intensity is  also mathematically represented as

      d =  \frac{P}{A}

So

    \beta  =  10dB *  log_{10}[\frac{P}{A* d_o} ]

=>   \frac{\beta}{10}  =  log_{10} [\frac{P}{A (l_o)} ]

From the logarithm definition

=>    \frac{P}{A  *  d_o}  =  10^{\frac{\beta}{10} }

=>      P =  A (d_o ) [10^{\frac{\beta }{ 10} } ]

Here P is the power of the sound wave

 and  A is the cross-sectional area of the sound wave  which is generally in spherical form

Now the power of the sound wave at the first position is mathematically represented as

               P_1 =  A_1 (d_o ) [10^{\frac{\beta_1 }{ 10} } ]

Now the power of the sound wave at the second  position is mathematically represented as

               P_2 =  A_2 (d_o ) [10^{\frac{\beta_2 }{ 10} } ]

Generally  power of the wave is constant at both positions  so  

    A_1 (d_o ) [10^{\frac{\beta_1 }{ 10} } ]  = A_2 (d_o ) [10^{\frac{\beta_2 }{ 10} } ]

      4 \pi r_1 ^2   [10^{\frac{\beta_1 }{ 10} } ]  = 4 \pi r_2 ^2   [10^{\frac{\beta_2 }{ 10} } ]

        r_2 =  \sqrt{r_1 ^2 [\frac{10^{\frac{\beta_1}{10} }}{ 10^{\frac{\beta_2}{10} }} ]}

       substituting value

        r_2 =   \sqrt{ 24^2 [\frac{10^{\frac{ 40}{10} }}{10^{\frac{80}{10} }} ]}

        r_2  =  0.24 \  m

     

7 0
3 years ago
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