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lara [203]
3 years ago
13

A source at rest emits light of wavelength 500 nm. When it is moving at 0.90c toward an observer, the observer detects light of

wavelength: 26 nm 115 nm 500 nm 2200 nm 9500 nm
Physics
1 answer:
Vesna [10]3 years ago
8 0

Answer:

The observer detects light of wavelength is 115 nm.

(b) is correct option

Explanation:

Given that,

Wavelength of source = 500 nm

Velocity = 0.90 c

We need to calculate the wavelength of observer

Using Doppler effect

\lambda_{o}=\sqrt{\dfrac{1-\beta}{1+\beta}}\lambda_{s}

Where, \beta=\dfrac{c}{v}

\lambda_{o}=\sqrt{\dfrac{c-0.90c}{c+0.90c}}\times500\times10^{-9}

\lambda_{o}=115\ nm

Hence, The observer detects light of wavelength is 115 nm.

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A small object has charge Q. Charge q is removed from it and placed on a second small object The two objects are placed I m apar
Whitepunk [10]

Answer:

q = Q/2

option c is correct

Explanation:

given data

charge = Q

distance r = 1 m

charge = q

to find out

what should q be

solution

we have given charge q is remove so

q1 = Q-q

q2 = q

we know by coulombs law force

force = kq1q2 / r²   .............1

put here value and we know k is constant

F = k (Q-q) q / 1

now take derivative charge q and put = 0

dF/dq = k d(Q-q)q / dq

so  k (Q-q)q =0

Q = 2q

q = Q/2

so option c is correct

4 0
3 years ago
A researcher is studying traffic patterns at an intersection before an upcoming construction project. As part of this investigat
Anna [14]

Answer:

Procedural is the answer

hope this helps

7 0
3 years ago
Read 2 more answers
An incident ray of light strikes a diamond at an angle of
lys-0071 [83]

Answer:

The angle of refraction is option b: 17°.

Explanation:

We can find the angle of refraction by using Snell's law:

n_{1}sin(\theta_{1}) = n_{2}sin(\theta_{2})

Where:

n₁: is the index of refraction of the medium 1 (air) = 1.0003  

n₂: is the index of refraction of the medium 2 (diamond) = 2.42

θ₁: is the angle of incidence = 45°

θ₂: is the angle of refraction =?

Hence, the angle of refraction is:

sin(\theta_{2}) = \frac{n_{1}sin(\theta_{1})}{n_{2}} = \frac{1.0003*sin(45)}{2.42} = 0.2922

\theta_{2} = 17 ^{\circ}

Therefore, the correct option is b: 17°.

I hope it helps you!

4 0
3 years ago
Read 2 more answers
A uniformly charged sphere has a potential on its surface of 450 V. At a radial distance of 8.1 m from this surface, the potenti
igomit [66]

Answer:

The radius of the sphere is 4.05 m

Explanation:

Given;

potential at surface, V_s = 450 V

potential at radial distance, V_r = 150

radial distance, l = 8.1 m

Apply Coulomb's law of electrostatic force;

V = \frac{KQ}{r} \\\\V_s = \frac{KQ}{r} \\\\V_r = \frac{KQ}{r+ l}

450 = \frac{KQ}{r} ------equation (i)\\\\150 = \frac{KQ}{r+8.1} ------equation (ii)\\\\divide \ equation (i)\ by \ equation \ (ii)\\\\\frac{450}{150} = (\frac{KQ}{r} )*(\frac{r+8.1}{KQ} )\\\\3 = \frac{r+8.1}{r}  \\\\3r = r + 8.1\\\\2r = 8.1\\\\r = \frac{8.1}{2} \\\\r = 4.05 \ m

Therefore, the radius of the sphere is 4.05 m

4 0
3 years ago
A watt is a unit of<br><br>light<br>power<br>force<br>motion<br>energy
Crazy boy [7]

The answer would be Power

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3 years ago
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