Answer:
C. g/cm³
Explanation:
The slope is measured by calculating the variation of the Y values over the X values between two points on a line.
So, the formula is: Slope = Δy/Δx
That means that we also take the units.
In this case, the Y-axis unit is in g, while the X-axis unit is in cm³.
Dividing a Y-variation over an X-variation will give you g/cm³.
In this case, let's assume the line passes through (10,100) (not exactly, but close enough for the example), and it passes through (0,0)
So the slope would be: (100-0) g / (10-0) cm³ = 10 g/cm³
Answer:
433903.8 N
Explanation:
From work energy theorem, the total work done is equivalent to change in kinetic energy. Kinetic energy is depedant on speed and since pile drive finally comes to rest, then final velocity is zero. Also, its initial velocity is not given. Therefore, the sum of work due to gravity and beam equals to zero. Work due to gravity is product of mass of pile driver, acceleration due to gravity and height while work due to beam is a product of force and distance. Substituting the given values then
2300*9.81*3+(F*0.156)=0
F=-433903.84615384615384615384615384615384615 N
Approximately, the magnitude of force is 433903.8 N and it acts upwards
Answer:
M = 175 kg
Explanation:
In the resolution of the harmonic oscillator movement of a system and a mass with a spring, the angular velocity is
w = √ k / m
Where k is the spring constant and m the mass
In this case the mass is the mass of the chair (m) plus the mass of the astronaut (M)
M all = m + M
The angular velocity and the period are related by
w = 2π / T
Substituting
2π / T = √(k/(m + M))
We calculate the astronaut's mass
4π² / T² = k / (m + M)
M = k T² / 4π² - m
M = 569 3.6² /(4π²) - 11
M = 186.8 - 11
M = 175 kg
Answer:
Explanation:
First at all let's understand what is moment of inertia (I). The moment of inertia of a body is the rotational analog of mass in linear motion, this is, it determines the force we should apply to the body to acquire a specific angular acceleration. But in the rotational case we should specify about what point we are going to rotate an object so always the moment of inertia is defined respect to an arbitrary axis. It's usual to use the center of mass as an axis of rotation, because it's an unique point where we can assume all the mass of the object is concentrated.The moment of inertia respect of an axis that passes through the center of mass is denoted 
.
Now, if the disk you're talking about has uniform density the center of mass is exactly at the geometrical center of the disk, and the moment of inertia of a disk as that is:
