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devlian [24]
2 years ago
13

How would the magnetic field lines appear for a bar magnet cut at the midpoint, with the two pieces placed end to end with a spa

ce in between such that the cut edges are closest to each other

Physics
1 answer:
Zarrin [17]2 years ago
4 0

Answer:

cutting the magnet in two parts each part has a North and South pole,

Explanation:

In magnetism the magnetic mono-poles are not found, this means that we do not have magnetic charges alone, therefore when cutting the magnet in two parts each part has a North and South pole, the magnetic lines go from the North pole to the South pole, see attached.

The density of the lines is approximately the intensity of the magnetic field.

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A box of mass 26 kg is initially at rest on a flat floor. The coefficient of kinetic friction between the box and the floor is 0
Kazeer [188]

Answer:

\Delta K = 52J

Explanation:

The change in kinetic energy will be simply the difference between the final and initial kinetic energies: \Delta K=K_f-K_i

We know that the formula for the kinetic energy for an object is:

K=\frac{mv^2}{2}

where <em>m </em>is the mass of the object and <em>v</em> its velocity.

For our case then we have:

\Delta K = K_f-K_i=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}=\frac{m(v_f^2-v_i^2)}{2}

Which for our values is:

\Delta K = \frac{m(v_f^2-v_i^2)}{2} = \frac{(26Kg)((2m/s)^2-(0m/s)^2)}{2} = 52J

3 0
3 years ago
A rugby player sits on a scrum machine that weighs 200 Newtons. Given that the coefficient of static friction is 0.67, the coeff
Trava [24]

a. 850 N is the minimum force needed to get the machine/player system moving, which means this is the maximum magnitude of static friction between the system and the surface they stand on.

By Newton's second law, at the moment right before the system starts to move,

• net horizontal force

∑ F[h] = F[push] - F[s. friction] = 0

• net vertical force

∑ F[v] = F[normal] - F[weight] = 0

and we have

F[s. friction] = µ[s] F[normal]

It follows that

F[weight] = F[normal] = (850 N) / (0.67) = 1268.66 N

where F[weight] is the combined weight of the player and machine. We're given the machine's weight is 200 N, so the player weighs 1068.66 N and hence has a mass of

(1068.66 N) / g ≈ 110 kg

b. To keep the system moving at a constant speed, the second-law equations from part (a) change only slightly to

∑ F[h] = F[push] - F[k. friction] = 0

∑ F[v] = F[normal] - F[weight] = 0

so that

F[k. friction] = µ[k] F[normal] = 0.56 (1268.66 N) = 710.45 N

and so the minimum force needed to keep the system moving is

F[push] = 710.45 N ≈ 710 N

4 0
1 year ago
ASAP! please help me MCQ. Thank you
Dmitriy789 [7]

Answer:13m

Explanation:

6 0
2 years ago
Read 2 more answers
Question 3(Multiple Choice Worth 3 points)
Burka [1]

The unit of measurement used in the metric system is  Meters.

The metric system makes use of measurements that we often see every day. these are used to measure length, weight, and capability. you will often see these as grams, kilograms, millimetres, centimeters, meters, milliliters, and liters. The metric machine is used all around the globe as it is easy to understand.

The metric system is a system of measurement that succeeded the decimalized system primarily based on the meter that had been added in France in the 1790s.

Metrics are measures of quantitative assessment normally used for comparing and tracking performance or manufacturing. Metrics may be used in a ramification of situations. Metrics are heavily trusted in the monetary evaluation of corporations with the aid of each inner manager and external stakeholders.

Learn more about the metric system here:-brainly.com/question/1837503

#SPJ9

8 0
1 year ago
If we've traveled with medium and displaces the particles perpendicular to the direction in which the wave is traveling. This ty
AlexFokin [52]
This type of wave is a transverse wave, or an S wave (secondary wave)
4 0
3 years ago
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