Answer:
A star that always remains above your horizon and appears to rotate around the celestial pole.
Explanation:
A) a star that is close to the north celestial pole: a circumpolar star could be close to the north celestial pole, but this answer is omitting the south celestial pole.
B) a star that is close to the south celestial pole: a circumpolar star could be close to the south celestial pole, but this answer is omitting the north celestial pole.
C) a star that always remains above your horizon and appears to rotate around the celestial pole: this is the definition of a circumpolar star.
D) a star that makes a daily circle around the celestial sphere: every star does this.
E) a star that is visible from the Arctic or Antarctic circles
: there are many starts visible from there that are not circumpolar.
Mass of Jupiter=1.9×10
27
㎏=M
1
Mass of Sun=1.99×10
30
㎏=M
2
Mean distance of Jupiter from Sun=7.8×10
11
m=r
G=6.67×10
−11
N㎡㎏
−2
Gravitational Force, F=
r
2
GM
1
M
2
F=
(7.8×10
11
)
2
6.67×10
−11
×1.9×10
27
×1.99×10
30
F=4.16×10
23
N
It's B because when you throw something it doesn't go up it slowly descends downward
To answer this question, it helps enormously if you know
the formula for momentum:
Momentum = (mass) x (speed) .
Looking at the formula, you can see that momentum is directly
proportional to speed. So if speed doubles, so does momentum.
If the car's momentum is 20,000 kg-m/s now, then after its speed
doubles, its momentum has also doubled, to 40,000 kg-m/s.
Answer:
7.98 m
Explanation:
In the given question,
distance above surface= 2 m
Distance penny from person = 8 m
Since the swimming pool is filled with water and atmosphere has air therefore the refractive index phenomenon will occur.
The refractive index of water: air is 4/3 (1.33).
Using the formula, 4/3 = real depth, apparent depth
real depth= 4/3 x apparent depth
Now, calculating apparent depth = 8 - 2
= 6 m
therefore, real depth = 4/3 x apparent depth
= 1.33 x 6
= 7.98
thus, 7.98 m is the real depth of water.
