Acceleration = (change in speed) / (time for the change)
Change in speed = (end speed) minus (start speed)
Change in speed = (25 m/s) - (10 m/s) = 15 m/s .
Acceleration = (15 m/s) / (6 sec) = 2.5 m/s² .
Average speed during the acceleration = (1/2) (10 m/s + 25 m/s)
Average speed during the acceleration = (1/2) (35 m/s)
Average speed during the acceleration = 17.5 m/s
Traveling at the average speed of 17.5 m/s for 6 sec, the car covers (17.5m/s x 6sec) = 105 meters.
The other way to solve it, using the formula: D = v₀t + (1/2) a T²
Distance = (initial speed)(time) + (1/2)(acceleration)(time²)
Distance = (10 m/s)(6 sec) + (1/2)(2.5 m/s²)(6.0sec)²
Distance = (60 m) + (1/2)(2.5 m/s²)(36 sec²)
Distance = (60 m) + (45 m) = 105 meters
