Answer:
C) acid-base neutralization
Explanation:
NaOH + CH₃COOH = CH₃COONa + H₂O
Break the solutions apart:
NaOH = Na⁺ + OH⁻
CH₃COOH = CH₃COO⁻ + H⁺
Combine the resulting solution after the reaction:
OH⁻ + H⁺ = H₂O
Answer:
The amount of water converted from liquid to gas with 6,768 joules is approximately 3.035 g
Explanation:
The amount of heat required to convert a given amount of liquid to gas at its boiling point is known as the latent heat of evaporation of the liquid
The latent heat of evaporation of water, Δ
≈ 2,230 J/g
The relationship between the heat supplied, 'Q', and the amount of water in grams, 'm', evaporated is given as follows
Q = m × Δ
Therefore, the amount of water, 'm', converted from liquid to gas at the boiling point temperature (100°C), when Q = 6,768 Joules, is given as follows;
6,768 J = m × 2,230 J/g
∴ m = 6,768 J /(2,230 J/g) ≈ 3.035 g
The amount of water converted from liquid to gas with 6,768 joules = m ≈ 3.035 g.
Following the law of conservation of mass, the mass percent of hydrogen in the resulting compound is 14.4%(wt/wt). This is assuming that all of the carbon reacts with all of the hydrogen. The solution is as follows:
mass % = mass hydrogen*100/total mass = 28.8*100/(28.8+171.2) = 14.4%
CuO(aq) + H2(g) → H2O(l) + Cu(s)
CuO= 64 + 16= 80g
1 mole of CuO → 1 mole of Cu
80g of CuO → 1 mole of Cu
20.50g of CuO → y
y= 20.50/80= 0.26mole.
Answer:
B. More reactant is added.
Explanation:
The question basically asks at which condition would the forward reaction be favoured.
The law of equilibrium states when a system at equilibrium is disturbed by, it would annul that change. In order to increase the forward reaction, more of the reactant should be added. In order to annul this change, the system would have to favour the reaction that deals with reducing the amount of reactant added.
The correct option is;
B. More reactant is added.
