The amount of Na₂SO₄ would be 15.09 grams
<h3>Stoichiometric calculation</h3>
From the equation of the reaction:
4NaOH + 2H₂SO₄ --> 2Na₂SO₄ + 4H₂O
Mole ratio of NaOH and Na₂SO₄ = 2:1
Mole of 8.50 grams of NaOH = 8.50/40
= 0.21 mole
Equivalent mole of Na₂SO₄ = 0.21/2
= 0.11 mole
Mass of 0.11 mole Na₂SO₄ = 0.11 x 142.04
= 15.09 grams
More on stoichiometric reactions can be found here: brainly.com/question/8062886
Answer: The final pressure is 75 mm Hg.
Explanation:
According to Boyle's law, at constant temperature the pressure of a gas in inversely proportional to volume.
Since, it is given that the temperature is constant. Hence, formula used is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that the final pressure is 75 mm Hg.
Since the nucleophile is the actual attacking molecule or molecule that starts the reaction and allows for further steps in the mechanism to occur, it is the limiting reagent, as based on the amount of the nucleophile you have, the reaction will tend to proceed until you run out. The excess would be the sodium hydroxide, it is union part of the solution.
Answer:
The potential wrt. calomel is 1.254 V
Explanation:
Given:
Potential wrt. silver chloride 
V
Potential wrt. saturated silver chloride 
V
Potential wrt. SCE 
V
Now potential wrt. hydrogen is given by,
V
And we find for potential wrt. calomel,
potential wrt. hydrogen + potential wrt. SEC
V
Therefore, the potential wrt. calomel is 1.254 V
From the equation, we see that the molar ratio of Fe : S required is:
8 : 1
The moles of Fe present are: 9.42/56 = 0.168
Moles of S = 68/(32 * 8) = 0.265
The molar ratio is:
1 : 1.6
Therefore, iron is the limiting reactant as it is present in a ratio lower than that required. The ratio of
Fe : FeS is
1 : 1
So 0.168 moles of FeS will form. The mass of FeS will be:
Mass = 0.168 * (56 + 32)
Mass = 14.78 grams
14.78 grams of FeS will be formed.
