1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Eva8 [605]
3 years ago
12

What is the calculated value of the cell potential at 298K for an

Chemistry
1 answer:
Tpy6a [65]3 years ago
4 0

The question is incomplete, here is the complete question:

What is the calculated value of the cell potential at 298 K for an  electrochemical cell with the following reaction, when the H₂  pressure is 6.56 x 10⁻² atm, the H⁺ concentration is 1.39 M, and  the Sn²⁺ concentration is 9.35 x 10⁻⁴ M?

2H^+(aq)+Sn(s)\rightarrow H_2(g)+Sn^{2+}(aq)

<u>Answer:</u> The cell potential of the given electrochemical cell is 0.273 V

<u>Explanation:</u>

For the given chemical equation:

2H^+(aq)+Sn(s)\rightarrow H_2(g)+Sn^{2+}(aq)

The half cell reactions for the given equation follows:

<u>Oxidation half reaction:</u> Sn(s)\rightarrow Sn^{2+}(aq)+2e^-;E^o_{Sn^{2+}/Sn}=-0.14V

<u>Reduction half reaction:</u> H_2+2e^-\rightarrow H_2(g);E^o_{2H^{+}/H_2}=0.0V

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=0.0-(-0.14)=0.14V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Sn^{2+}]\times p_{H_2}}{[H^+]^2}

where,

E_{cell} = electrode potential of the cell = ?

E^o_{cell} = standard electrode potential of the cell = +0.14 V

n = number of electrons exchanged = 2

[H^{+}]=1.39M

[Sn^{2+}]=9.35\times 10^{-4}M

p_{H_2}=6.56\times 10^{-2}atm

Putting values in above equation, we get:

E_{cell}=0.14-\frac{0.059}{2}\times \log(\frac{(9.35\times 10^{-4})\times (6.56\times 10^{-2})}{(1.39)^2})\\\\E_{cell}=0.273V

Hence, the cell potential of the given electrochemical cell is 0.273 V

You might be interested in
If a radioisotope has a half-life of 4 years, how much remains of a starting amount of 40 grams after 16 years have passed?
Gwar [14]

Answer:

only 2.5 grams will be present after 16 years have passed

5 0
3 years ago
What is a solid solution of a metal or nonmetal dissolved in a metal called?
irina [24]
I think this is alloys...................
3 0
3 years ago
Read 2 more answers
6. Lysozyme is an enzyme that hydrolyzes sugar linkages in the bacterial cell wall and was first discovered by Alexander Fleming
balu736 [363]

Answer:

See explaination

Explanation:

The Cys3-cys97 and cys21-cys142 disulfides restrict the unfolded state of lysozyme enzyme to a class of more compact structures with a less exposed hydrophobic surface, compared to the unfolded states of reduced/non-crosslinked lysozyme. there are 2 major factors which lead to the stabilization of lysozyme due to disulfide bonds-

1- increase in the loop size due to the formation of disulfide bonds that leads to an increase in the even entropic effect.

2- the region formed should be flexible. the strain energy due to the formation of the disulfide bond is lower.

cys21-cys142 has a higher Tm than the cys3-cys97 because it involves flexible parts of the molecule. 21 and 142 residues are located on opposite sides of the active-site cleft where significant hinge-bending motion is seen. this introduces minimal strain in the protein.

7 0
3 years ago
How many grams of CaCl2 are in 250 mL of 2.0 M CaCl2?
Tom [10]
The answer is:  " 56 g CaCl₂ " .
__________________________________________________________

Explanation:
__________________________________________________________
2.0 M CaCl₂  = 2.0 mol CaCl₂ / L  ; 

Since: "M" = "Molarity" (measurement of concentration); 

                  = moles of solute per L {"Liter"} of solution.
__________________________________________________________
Note the exact conversion:  1000 mL = 1 L . 

Given: 250 mL ;   

250 mL = ?  L  ?  ;  


250 mL * (1 L / 1000 L) =  (250/1000) L = 0.25 L . 
___________________________________________________________
 
(2.0 mol CaCl₂ / L ) * (0.25L) = (2.0) * (0.25) mol  = 0.50 mol CaCl₂ ;

We have: 0.50 mol CaCl₂ ;  Convert to "g" (grams):

→ 0.50 mol CaCl₂  .
___________________________________________________________
1 mol CaCl₂ = ? g ?

From the Periodic Table of Elements:

1 mol Ca = 40.08 g

1 mol Cl  =  <span>35.45 g .
</span>
There are 2 atoms of Cl in " CaCl₂ " ;  

→ Note the subscript, "2", in the " Cl₂ " ; 
__________________________________________________________
So, to calculate the molar mass of "CaCl₂" :

40.08 g  +  2(35.45 g) = 

40.08 g  +  70.90 g = 110.98 g ;  round to 4 significant figures; 

                                 → round to 111 g/mol .
__________________________________________________________
So:

→  0.50 mol CaCl₂  = ? g CaCl₂  ? ; 

→  0.50 mol CaCl₂ * (111 g CaCl₂ / mol CaCl₂) ;

                                             = (0.50) * (111 g) CaCl₂ ;

                                             =  55.5 g CaCl₂  ;

                                                → round to 2 significant figures; 

                                                →  56 g CaCl₂ .
___________________________________________________________
The answer is:  " 56 g CaCl₂ " .
___________________________________________________________
6 0
3 years ago
Read 2 more answers
Complete the following radioactive decay problem.<br>222 86 RN to 4 2 HE + ?​
Andreas93 [3]

Answer:

₈₆²²²Rn    →   ₈₄Po²¹⁸  +  H₂⁴

Explanation:

The given nuclear reaction shows alpha decay.

₈₆²²²Rn    →   ₈₄Po²¹⁸  +  H₂⁴

Properties of alpha radiations:

Alpha radiations are emitted as a result of radioactive decay. The atom emit the alpha particles consist of two proton and two neutrons. Which is also called helium nuclei. When atom undergoes the alpha emission the original atom convert into the atom having mass number less than 4  and atomic number less than 2 as compared to parent atom the starting atom.

Alpha radiations can travel in a short distance.

These radiations can not penetrate into the skin or clothes.

These radiations can be harmful for the human if these are inhaled.

These radiations can be stopped by a piece of paper.

₉₂U²³⁸   →   ₉₀Th²³⁴  + ₂He⁴  + energy

8 0
3 years ago
Other questions:
  • Choose the pieces of evidence that supported the existence of Pangaea and continental drift theory.
    10·2 answers
  • Jerome is learning how the model of the atom has changed over time as new evidence was gathered. He has images of four models of
    10·2 answers
  • The secondary structure of a protein refers to the ___________.a. three-dimensional folded structure of the protein. b. configur
    6·1 answer
  • Draw the structure of an alcohol with the molecular formula C5H12O that exhibits the following signals in its 13C NMR spectra: (
    14·1 answer
  • Which of the following is one of the defining features of a hurricane?
    9·2 answers
  • Sugar is easily soluble in water and has a molar mass of 342.30 g/mol. What is the molar concentration of a 259.8 mL aqueous sol
    15·1 answer
  • A team of geologists is surveying on a mountain. They come across a newly formed stream. The stream is flowing at an average rat
    12·1 answer
  • PLEASE SOEMBODY HELP ME AND PLEASE HURRY
    13·1 answer
  • How do i draw these lines?
    6·1 answer
  • I REALLY NEED THE HELP
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!