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mixer [17]
3 years ago
12

Which pairs of polygons are congruent?

Mathematics
1 answer:
Roman55 [17]3 years ago
5 0
I would say that its pair 1 and 3
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Please help me with this problem im having trouble answering this
adell [148]

Answer:

tgtftgrfrfrdrxdrdrcrcrcrxrxrxrc

4 0
3 years ago
I don’t know how to do this help :(
katen-ka-za [31]
A of trapezium = ((a+b)/2)(h)
A = ((10+10+4)/2)(8)
A = (24/2)(8)
A = 12(8)
A = 94
The area is 94ft²
5 0
3 years ago
The function below models the voltage, in volts, of a certain alternating current after x seconds, where A and b are positive co
Katarina [22]

First of all, we can just ignore A, it has no effect but to vertically stretch our cosine.

If it was only f(x)=cosx, the function would be invertible as long as it's confined between 0 and \pi. Now, the argument of our cosine is not x but bx. It means that it won't stop at \pi, but at \frac{\pi}{b}.

Another way to think about it, "what should i replace x with so I get \pi inside the cosine?"

4 0
3 years ago
The sum of squares of two
Elanso [62]

Answer:

the product of the 2 numbers is 22

Step-by-step explanation:

x² + y² = 80

(x - y)² = 36

=>

x - y = 6

or y - x = 6

let's start with the first one x-y=6

x = 6 + y

=>

(6+y)² + y² = 80

y² + 6y +6y + 36 + y² = 80

2y² + 12y + 36 = 80

2y² + 12y - 44 = 0

y² + 6y - 22 = 0

the solution of a quadratic equation

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case here we have an squadron in y.

a=1

b=6

c=-22

(-6 ± sqrt(36 + 4×22))/2 = (-6 ± sqrt(36+88))/2 =

= (-6 ± sqrt(124))/2 = (-6 ± sqrt(4×31))/2 =

= (-6 ± 2×sqrt(31))/2 = -3 ± sqrt(31)

y1 = -3 + sqrt(31)

y2 = -3 - sqrt(31)

=>

x1 = 6 + -3 + sqrt(31) = 3 + sqrt(31)

x2 = 3 - sqrt(31)

control :

(-3 + sqrt(31))² + (3 + sqrt(31))² = 80

9 - 3 sqrt(31) - 3 sqrt(31) + 31 + 9 +3 sqrt(31) + 3 sqrt(31) + 31 = 80

9 + 31 + 9 +31 = 80

18 + 62 = 80

80 = 80 correct

solving now for y-x=6

delivers exactly the same calculations, just with x and y trading places.

so, the resulting 2 number pairs are the same.

the product of the 2 numbers :

(3 + sqrt(31))(-3 + sqrt(31)) = -9 - 3 sqrt(31) + 3 sqrt(31) + 31 =

= -9 + 31 = 22

(3 - sqrt(31))(-3 - sqrt(31)) = -9 + 3 sqrt(31) - 3 sqrt(31) + 31 =

= 22

so, the product is the same in both cases.

6 0
2 years ago
4x+1=9+4y please help me solve for x please show step by step I’m very confused
Inessa05 [86]

Answer:

<em>x - y = 2</em>

Step-by-step explanation:

First of all, you would combine like terms, giving you 4x - 4y + 1 = 9.

Next, subtract the numbers, which gives you 4x - 4y = 8.

Finally, divide both sides by 4, which will come to the conclusion of x - y = 2, the simplest form of which this equation can be broken down to.

7 0
3 years ago
Read 2 more answers
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