Answer:
V = 20.2969 mm^3 @ t = 10
r = 1.692 mm @ t = 10
Step-by-step explanation:
The solution to the first order ordinary differential equation:
Using Euler's method
Where initial droplet volume is:
Hence, the iterative solution will be as next:
- i = 1, ti = 0, Vi = 65.45
- i = 2, ti = 0.5, Vi = 63.88
- i = 3, ti = 1, Vi = 62.33
We compute the next iterations in MATLAB (see attachment)
Volume @ t = 10 is = 20.2969
The droplet radius at t=10 mins
The average change of droplet radius with time is:
Δr/Δt = 
The value of the evaporation rate is close the value of k = 0.08 mm/min
Hence, the results are accurate and consistent!
Answer: 120 seconds
Step-by-step explanation: In order to find the maximum value of a function, you can take the derivative of the function and equalize the result to 0.
f'(x)=(-3x^2 + 12x)'=-6x+12=0
x=2
When x is 2, the function will reach its maximum value.
f(2)=-3(2)^2 + 12.2 = -12 + 24 = 12
The maximum value (f(x)) is equal to 12 and the time passed is 2 minutes which is equal to 120 seconds.
We can easily get the quarts per hour rate by dividing the number of quarts by the number of hours:
Now that we have the quarts per hour rate, we can easily address the question: the factory could make
quarts in 48 hours, with a daily rate of
quarts per day
Answer:
(![\sqrt[5]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%7D)
)^7
Step-by-step explanation:
to cancel out the radical you do the exponent inside and divide it by the out side one so it will be 7/5 so make it x to the expontent of 7/5 and to do rational exponets it will be (^5radicalx)^7
