ANSWER
My answer is in the photo above
The amount of time saved on the 86.0 mile trip from Tulsa entrance to Oklahoma City is 0.42 hours
<h3>What is time?</h3>
Time is the measurement of a past, present, or future event. The S.I unit of time is seconds (s)
To get the time that was saved on the 8.6-mile trip, we use the formula below.
Formula:
- Ts = (d/v₁)-(d/v₂)................. Equation 1.
Where:
- Ts = Time saved on the trip
- d = distance covered during the trip
- v₁ = Initial legal speed limit
- v₂ = final/current legal speed limit.
From the question,
Given:
- d = 86.0 mile
- v₁ = 55.0 mi/h
- v₂ = 75.0 mi/h
Substitute these values into equation 1
- Ts = (86/55)-(86/75)
- Ts = 1.564-1.147
- Ts = 0.42 h.
Hence, The amount of time saved on the 86.0 mile trip from Tulsa entrance to Oklahoma City is 0.42 hours.
Learn more about time here: brainly.com/question/13893070
Answer:
Work done by the little rocket engine = 19.6 Joules.
Explanation:
We know that work = force x displacement.
Force = weight of rocket = 4.9 N
Displacement = 5 meter.
So work done by the little rocket engine = Weight of rocket x displacement.
Work done by the little rocket engine = 4.9 x 4 = 19.6 J
Work done by the little rocket engine = 19.6 Joules.
The correct options are: B, C and D.
In fact:
- B is true, because the motion of the projectile can be decomposed in two independent motions on the x and y axis. On the x-axis, there is no acceleration; while on the y-axis, the projectile is accelerating towards the ground with

(acceleration of gravity)
- C is true, because the two motions on the horizontal and vertical direction are independent. In particular, the horizontal motion is a uniform motion (constant velocity), while the vertical motion is a uniformly accelerated motion (because of the gravitational acceleration g acting on the projectile)
- D is true, in fact (if we neglect air resistance) gravity is the only force acting on the projectile.