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3 years ago

Please don’t troll. I need someone to actually answer these questions.

Physics

1 answer:

mash [69]3 years ago

4 0

Answer:

-3+3 i think this is the answer

Explanation:

i think you can ask someone else sorry

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If limestone is exposed to the right amount of heat and pressure what might it become

Sedbober [7]

It would become a type of metamorphic rock. Most likely marble

4 0

3 years ago

A baseball has a mass of 0.15kg .What is the net force on the ball if it's acceleration is 40.0m/sw

kvasek [131]

By Newton's second law, we have

$F=ma$

So, in order to give a 0.15kg body an acceleration of 40m/s^2, you need a force of

$F=0.15\cdot 40 = 6N$

7 0

3 years ago

Any help is appreciated please

stiv31 [10]

Answer:

C. It speeds up, and the angle increases

Explanation:

We can answer by using the Snell's law:

$n_i sin \theta_i = n_r sin \theta_r$

where

$n_i, n_r$ are the refractive index of the first and second medium

$\theta_i$ is the angle of incidence (measured between the incident ray and the normal to the surface)

$\theta_r$ is the angle of refraction (measured between the refracted ray and the normal to the surface)

In this problem, light moves into a medium that has lower index of refraction, so

$n_r < n_i$

We can rewrite Snell's law as

$sin \theta_r =\frac{n_i}{n_r}sin \theta_i$

and since

$\frac{n_i}{n_r}>1$

this means that

$sin \theta_r > sin \theta_i$

which implies

$\theta_r > \theta_i$

so, the angle increases.

Also, the speed of light in a medium is given by

$v=\frac{c}{n}$

where c is the speed of light and v the refractive index: we see that the speed is inversely proportional to n, therefore the lower the index of refraction, the higher the speed. So, in this problem, the light will speed up, since it moves into a medium with lower index of refraction.

4 0

3 years ago

A 2.5 kg , 20-cm-diameter turntable rotates at 150 rpm on frictionless bearings. Two 500 g blocks fall from above, hit the turnt

emmainna [20.7K]

The concepts required to solve this problem are those related to the conservation of the angular momentum and the moment of inertia of the disk. We will begin by calculating the moment of inertia of the disc, then the moment of inertia of the disc after the two two blocks hits and sticks to the edges of the turn table. In the end we will apply the conservation theorem.

The radius is given as,

$R = \frac{20cm}{2} = 10cm = 0.1m$

When a block falls from above and sticks to the turn table, the moment inertia of the turntable increases.

Since two blocks are stick to the turn table, the total final moment of inertia of the turntable is the sum moment of inertias of individual turntable, and two blocks.

$I_1 = \frac{1}{2} MR^2$