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3 years ago

Please don’t troll. I need someone to actually answer these questions.

Physics

1 answer:

mash [69]3 years ago

4 0

Answer:

-3+3 i think this is the answer

Explanation:

i think you can ask someone else sorry

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Certain neutron stars (extremely dense stars) are believed to be rotating at about 50 rev/s. If such a star has a radius of 15 k

vesna_86 [32]

Answer: $M=49.95\times 10^{26} kg$

Explanation:

Given

$N=50 rev/s$

$\omega =2\pi N$

$\omega =2\pi \cdot 50=314.2 rad/s$

radius of neutron star $r=15 km$

Centripetal force on material having mass m is given by

$F_c=\frac{mv^2}{r}$

Gravitational Force between neutron star and mass m is

$F_g=\frac{GMm}{r^2}$ ,where M=mass of Neutron star

equating centripetal Force and Gravitational Pull

$\frac{mv^2}{r}=\frac{GMm}{r^2}$

$M=\frac{v^2r}{G}$

$M=\frac{\omega ^2r^3}{G}$

$M=\frac{(314.2)^2\times (15000)^3}{6.67\times 10^{-11}}$

$M=\frac{0.4995\times 10^17}{10^{-11}}$

$M=49.95\times 10^{26} kg$

7 0

3 years ago

A ladybug falls into small hole. it takes 8.6s for the ladybug to hit the bottom. how deep is the hole? (take g=9.81 m/s²)

Jobisdone [24]

Answer:

Length of hole (s) = 362.77 m (Approx)

Explanation:

Given:

Time taken to hit the bottom (t) = 8.6 s

Acceleration due to gravity (g) = 9.81 m/s²

Find:

Length of hole (s) = ?

Computation:

Initial velocity (u) = 0 m/s

S = ut +1/2(gt²)

S = (0)(8.6) +1/2(9.81)(8.6)(8.6)

S = 1/2(9.81)(8.6)(8.6)

S = 362.7738

Length of hole (s) = 362.77 m (Approx)

4 0

3 years ago

Which of the following is an example of the electrostatic force acting in an atom?

777dan777 [17]

A proton repelling another proton

Like charges of the protons would repel one another.

7 0

3 years ago

Read 2 more answers

Answer needed asap............

NikAS [45]

I): Speed=Distance/Time
=65-30 km/12:30-12:00 hrs
=35 km/00:30hrs
=3500 m/1800 s
=1.94m/s

ii): Average Speed=Total Distance/Total Time
=100000 m/7200 s
=13.88 m/s

iii):No because it has different speeds at
different time intervals

5 0

3 years ago

Read 2 more answers

Find the moment of force of 60 Newton about an axis of rotation at distance 20 cm from the force

777dan777 [17]

Answer:

10 N.m

Explanation:

Force * Perpendicular distance.

= 20 N * 0.5 m

= 10 N.m

8 0

3 years ago