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3 years ago

5th Grade U.S Studies Weekly- Week 24 Answer Key

Mathematics

1 answer:

Georgia [21]3 years ago

3 0

You should try and put it in another way it doesn’t make sense

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One x-intercept for a parabola is at the point (-2,0).

BARSIC [14]

You can find the x intercept by setting y to 0 and factor the equation.

0=2x^3+3x-2
0=(2x-1)(x+2)

We can make this equation =0 if x is -2 and 1/2.

So the x intercepts are (-2,0) and (0.5,0)

8 0

3 years ago

Compare 9 ⋅ 104 to 3 ⋅ 102. 9 ⋅ 104 is 3 times larger than 3 ⋅ 102. 9 ⋅ 104 is 30 times larger than 3 ⋅ 102. 9 ⋅ 104 is 300 time

lord [1]

Answer:

Correct option is:

9 ⋅ 104 is 3 times larger than 3 ⋅ 102

Step-by-step explanation:

9 ⋅ 104 = 3×3×104

3 ⋅ 102 = 3×102

104 is near to 102

Let 104 ≈ 102

3×104 ≈ 3×102

3×3×104 ≈ 3×3×102 = 3(3×102)

i.e. 9 · 104 ≈ 3(3 · 102)

Hence, Correct option is:

9 ⋅ 104 is 3 times larger than 3 ⋅ 102

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4 years ago

(GIVING BRAINLIYEST)<br> 7. what is the volume of these 2 objects

babunello [35]

figure #1

smaller part

4x7x2= 56m

larger part

4x3x7= 84m

84+56= 140m³

figure #2

smaller part

2x4x3= 24m

larger part

4x4x12= 192m

192+24= 216in³

6 0

3 years ago

Read 2 more answers

From ground level to the tip of the torch, the statue of Liberty and its pedestal are 92.99 meters tall. The pedestal is 0.89 me

CaHeK987 [17]

Simply subtract 0.89 from 92.99 meters:
<span>92.99 - 0.89 = 92.10 </span>

3 0

3 years ago

A 16-inch candle is lit and burns at a constant rate of 0.8 inches per hour. Let t represent the number of hours since the candl

Tamiku [17]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

The initial length of the candle is 16 inch. It also given that, it burns with a constant rate of 0.8 inch per hour.

After one hour since the candle was lit, the length of the candle will be (16 - 0.8) = 15.2 inch.

After two hour since the candle was lit, the length of the candle will be (15.2 - 0.8) = 14.4 inch. The length of the candle after two hours can also be represented by {16 - 2(0.8)}.

Hence, the length of the candle after t hours when it was lit can be represented by the function, $f(t) = 16 - 0.8t$ . $f(t) = 0$ at t = 20.

The domain of the function is 0 to 20.

The range is 0 to 16.

8 0

4 years ago