what is range of the inverse of the relation {(1, 7), (-2, 4), (5, 6), (2, 8)} A. {1, 2,5} B. {-4, 6, 7, 8} C. {1, 5} D. {-4, 7,
Rufina [12.5K]
The answer should be the domain of this relation. {-2, 1, 2, 5} but I do not see that as one of your answer choices.
The inverse of a relation is when you switch the domain and range. In other words, the domain of the original relation becomes the range of the inverse.
Answer:
p = 8
Step-by-step explanation:
Let one root of the eqn. be alpha . Other root is 1/alpha .
We know that product of both roots of an quadratic eqn. is c/a where "c" is the co-efficient of the constant & "a" is the co-efficient of x^2.
Here "c" is p-4 & "a" is 4. And the product of roots is 1 ( ∵ prdouct of a number and its reciprocal is 1 )
Answer:
angle s = 22
angle r = 117
angle q = 41
Step-by-step explanation:
so all of the angles equal to 180 degrees in a triangle
so you add all of t he angles like this:
x+5x+7x+2x-3=180
collect all of the like terms,
8x + 4 = 180
subtract 4 from both sides, which leaves you with 8x = 176
divide both sides by 8 leaving x on its own.
x = 22
angle s = 22
angle r = (5x22)+7 which is 117
angles q = (2x22)-3 which is 41
What is the rest of the question or problem?
Answer is a very easy answer
