How do i find volume of cone

Artemon [7]

20 x 18 x 5= 1,800
20 times 18 equals 360, then you mutiply 5 and get 1,800

8 0

2 years ago

4 times the measure of the complement of an angle is equal to 2/3 the measure of the original's angles's supplement. what is the

scoundrel [369]

Answer:

72 degrees.

Step-by-step explanation:

If the angle is x degrees its complement is 90-x degrees and it's supplement is 180-x degrees.

4(90-x) = 2/3(180 - x)

360 - 4x = 120 - 2/3 x

360 - 120 = -2/3 x + 4x

240 = -2/3 + 12/3 x

240 = 10/3 x

x = 240 * 3/10

x = 72 degrees.

7 0

2 years ago

The service life of a battery used in a cardiac pacemaker is assumed to be normally distributed. A random sample of ten batterie

Fittoniya [83]

Answer:

The confidence interval is $25.16 < \mu < 26.85$

Step-by-step explanation:

From the question we are given a data set

25.5, 26.1, 26.8, 23.2, 24.2, 28.4, 25.0, 27.8, 27.3, and 25.7.

The mean of the this sample data is

$\= x = \frac{\sum x_i}{n}$

where is the sample size with values n = 10

$\= x = \frac{25.5+ 26.1+ 26.8+23.2+ 24.2+ 28.4+ 25.0+ 27.8+ 27.3+ 25.7}{10}$

$\= x = 26$

The standard deviation is evaluated as

$\sigma = \sqrt{\frac{\sum (x-\= x)}{n} }$

substituting values

$= \sqrt{\frac{ ( 25.5-26)^2, (26.1-26)^2, (26.8-26)^2, (23.2-26)^2}{10} }$

$\cdot \ \cdot \ \cdot \sqrt{\frac{ ( 24.2-26)^2, (28.4-26)^2+( 25.0-26)^2+ (27.8-26)^2+( 27.3-26)^2+( 25.7-26)^2}{10} }$

$\sigma = 1.625$

The confidence level is given as 90% hence the level of significance is calculated as

$\alpha = 100 -90$

$\alpha =10$ %

$\alpha = 0.10$

Now the critical values of $\frac{\alpha }{2}$ is obtained from the normal distribution table as

$Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining the critical values of $\frac{\alpha }{2}$ instead of $\alpha$ is because we are considering two tails of the area under the normal curve

The margin of error is evaluated as

$MOE = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

substituting values

$MOE = 1.645 * \frac{1.625 }{\sqrt{10} }$

$MOE = 0.845$

The 90%, two sided confidence interval is mathematically evaluated as

$\= x - MOE < \mu < \= x + MOE$

$26 - 0.845 < \mu < 26 + 0.845$

$25.16 < \mu < 26.85$

Given that the lower and the upper limit is greater than 25 then we can assure the manufactures that the battery life exceeds 25 hours

5 0

3 years ago

Someone please help i don’t understand

WITCHER [35]

Answer:

Your answers for the row #6 are (going from left to right) 7, 8, 9, 10, 11, 12

Step-by-step explanation:

Explanation-If you look at each column, you can see that if you take the top number on any row by its side number, you just add the two.

Take the number one on the left side and add it to the number one on the top column. 1 + 1=2. So therefore, that is why there is a 2 in the answer box. 1 + 2=3, which is the next answer. It's like a pattern. Just take the number on the side and add it to the top letter until you get to the end of the row.

Example- In the first row, it goes 1, 2, 3, 4, 5, 6, 7 for a reason. The reason you have 2 for the first orange box is because 1 + 1 = 2

3 0

2 years ago

DO NOT SKIP LETS SO WHOS SMART ENOUGH TO ANSWER THESE 2 PROBLEMS I CHALLENGE YOU!!

rodikova [14]

Q 16. The energy is 308.7 J.

Q 17. The energy is 896000 J.

Step-by-step explanation:

Q 16. Given,

Mass (m) of the carriage and baby = 1.5 kg

Height (h) = 21 m

To find the energy.

We will find the potential energy as it rests at the top.

Formula

Potential energy = mgh where g be the gravitational force of the earth = 9.8m/s²

So,

Energy = 1.5×9.8×21 J

= 308.7 J.

Hence,

The energy is 308.7 J.

Q 17. Given,

Mass (m) = 1120 kg

Speed (v) = 40 m/s

To find out the energy.

We will find out the kinetic energy as the car is in motion.

Formula

Kinetic energy = $\frac{1}{2}$ mv²

So,

Energy = $\frac{1}{2}$ ×1120×40² J

= 896000 J

Hence,

The energy is 896000 J.

7 0

3 years ago