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olga2289 [7]
3 years ago
12

raw three water molecules interacting with each other. Indicate hydrogen-bonding with dashed lines. Show lone pairs!

Chemistry
1 answer:
Katyanochek1 [597]3 years ago
6 0

Answer:

The answer is in the image.

Explanation:

Water molecules are drawn in blue, with the hydrogen bonds indicated with dashed lines. The oxygen lone pairs are drawn as red dots. I also marked the areas of negative density (high concentration of electrons) and positive density (low concentration of electrons).

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A solution of aqueous ammonium sulfate has a mass of 482 grams. Calculate the mass of ammonium sulfate in solution if the mass p
umka2103 [35]

Answer:

The answer to your question is the mass of solute = 53.5 g

Explanation:

Data

mass of solution = 482 g

mass of solute = ?

mass percent = 11.1 %

Mass percent is a unit of concentration. It measures the mass of the solute divided by the total mass of the solution

Process

1.- Write the formula

        Mass percent = mass of solute / mass of solution x 100

-Solve for mass of solute

          mass of solute = Mass percent x mass of solution / 100

2.- Substitution

          mass of solute = 11.1 x 482 / 100

3.- Simplification

          mass of solute = 5350.2 / 100

4.- Result

          mass of solute = 53.5g

6 0
3 years ago
What is the molecularity of this elementary step?
dybincka [34]
The correct answer is b. bimolecular
3 0
3 years ago
Read 2 more answers
Match the part of the wave to the diagram
erik [133]

Answer:

The first high part is Q4, then the low part is Q7, the following high part is Q6, and the energy moving from the next two high points is Q5.

Explanation:

The first high part is Q4, then the low part is Q7, the following high part is Q6, and the energy moving from the next two high points is Q5 because of the diagram.

5 0
3 years ago
Number of sodium atom(s) in salt (NaCl)
asambeis [7]

Answer:

NaCl consists of one atom each of sodium and chlorine. Hence, each molecule of NaCl has 2 atoms total.

Explanation:

6 0
3 years ago
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the vapor pressure of a naqueous solution is found to be 24.9 mmgh at 25C. what is the mole fraction of solute in this solution?
Gekata [30.6K]

Answer:

Mole fraction of solute is 0.0462

Explanation:

To solve this we use the colligative property of lowering vapor pressure.

First of all, we search for vapor pressure of pure water at 25°C  = 23.8 Torr

Now, we convert the Torr to mmHg. Ratio is 1:1, so 23.8 Torr is 23.8 mmHg.

Formula for lowering vapor pressure is:

ΔP = P° . Xm

Where ΔP = P' (Vapor pressure of solution) - P° (Vapor pressure of pure solvent)

Xm = mole fraction

24.9 mmHg - 23.8 mmHg = 23mmHg . Xm

Xm = (24.9 mmHg - 23.8 mmHg) /  23mmHg

Xm = 0.0462

8 0
3 years ago
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