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ra1l [238]
2 years ago
11

Please help! Is there another way that 3.40x10^-19J can be imputed on a computer. I have the right answer but it is wrong.

Chemistry
1 answer:
r-ruslan [8.4K]2 years ago
4 0

The energy of the photon with the wavelength of 584 nm is 3.4×10¯¹⁹ J

<h3>How to determine the frequency of the photon</h3>
  • Wavelength (λ) = 584 nm = 584×10⁻⁹ m
  • Speed of light (v) = 3×10⁸ m/s
  • Frequency (f) = ?

f = v / λ

f = 3×10⁸ / 584×10⁻⁹

f = 5.14×10¹⁴ Hz

<h3>How to determine the energy</h3>
  • Planck's constant (h) = 6.626×10¯³⁴ Js
  • Frequency (f) = 5.14×10¹⁴ Hz
  • Energy (E) =?

E = hf

E = 6.626×10¯³⁴ × 5.14×10¹⁴ Hz

E = 3.4×10¯¹⁹ J

Learn more about energy:

brainly.com/question/10703928

#SPJ1

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Explanation:

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4 years ago
You have a solution with 2.52 moles of isopropanol (C3H8O). The solution weighs 521 grams. What is the percent composition of is
Kamila [148]

Answer:

The Percent composition of isopropanol in the mixture is 29.07 %

Explanation:

Step 1: Data given

Number of moles isopropanol (C3H8O) = 2.52 moles

Mass of the solution = 521 grams

Molar mass of isopropanol (C3H8O) = 60.1 g/mol

Step 2: Calculate mass of isopropanol

Mass isopropanol = moles isopropanol * molar mass isopropanol

Mass isopropanol = 2.52 moles * 60.1 g/mol

Mass isopropanol = 151.45 grams

Step 3: Calculate the percent composition of isopropanol in the mixture

Percent composition of isopropanol = (mass isopropanol / total mass of mixture) * 100 %

Percent composition of isopropanol = (151.45 grams / 521 grams ) * 100 %

Percent composition of isopropanol = 29.07 %

The Percent composition of isopropanol in the mixture is 29.07 %

8 0
4 years ago
Read 2 more answers
A mixture of sodium bicarbonate and ammonium bicarbonate is 75.9% bicarbonate by mass. what is the mass percent of sodium bicarb
Lorico [155]
Answer: 24.1%,  under below assumptions.

Justification:

The question is quite ambiguous, because one of the data is not clearly stated. It says that the mixture consists on two compounds:

- sodium bicarbonate, and
- ammonium bicarbonate

.After, it says that it is 75.9 % bicarbonate, but it does not specify which bicarbonate, it might be the sodium bicarbonate or the ammonium bicarbonate. It is apparent that you omitted that information by error.

Given that later, the question is <span>what the mass percent of sodium bicarbonate is in the mixture, it is supposed that the 75.9% content is of ammonium bicarbonate.

With that said, you can calculate the mass percent of sodium bicarbonate, because there are only two compounds and so you know that both add up the 100% of the mixture.

In formulas:

100% = %m/m sodium bicarbonate + %m/m ammonium bicarbonate = 100%

=> % m/m sodium bicarbonate = 100% - % m/s ammonium bicarbonate

=> % sodium bicarbonate = 100% - 75.9% = 24.1%

Answer: 24.1%
</span>
8 0
4 years ago
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