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ra1l [238]
2 years ago
11

Please help! Is there another way that 3.40x10^-19J can be imputed on a computer. I have the right answer but it is wrong.

Chemistry
1 answer:
r-ruslan [8.4K]2 years ago
4 0

The energy of the photon with the wavelength of 584 nm is 3.4×10¯¹⁹ J

<h3>How to determine the frequency of the photon</h3>
  • Wavelength (λ) = 584 nm = 584×10⁻⁹ m
  • Speed of light (v) = 3×10⁸ m/s
  • Frequency (f) = ?

f = v / λ

f = 3×10⁸ / 584×10⁻⁹

f = 5.14×10¹⁴ Hz

<h3>How to determine the energy</h3>
  • Planck's constant (h) = 6.626×10¯³⁴ Js
  • Frequency (f) = 5.14×10¹⁴ Hz
  • Energy (E) =?

E = hf

E = 6.626×10¯³⁴ × 5.14×10¹⁴ Hz

E = 3.4×10¯¹⁹ J

Learn more about energy:

brainly.com/question/10703928

#SPJ1

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I think the right answer is 2.5
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A sample of sodium sulfite has a mass of 2.80 g.
Gnom [1K]

<u>Answer:</u>

<u>For a:</u> The number of sodium ions in given amount of sodium sulfite are 2.65\times 10^{22}

<u>For b:</u> The number of sulfite ions in given amount of sodium sulfite are 1.325\times 10^{22}

<u>For c:</u> The mass of one formula unit of sodium ions is 2.09\times 10^{-22} grams

<u>Explanation:</u>

The chemical formula of sodium sulfite is  Na_2SO_3. It is formed by the combination of 2 sodium (Na^+) ions and 1 sulfite (SO_3^{2-}) ions

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of sodium sulfite = 2.80 g

Molar mass of sodium sulfite = 126 g/mol

Putting values in above equation, we get:

\text{Moles of sodium sulfite}=\frac{2.80g}{126g/mol}=0.022mol

  • <u>For a:</u>

Moles of sodium ions in sodium sulfite = (2 × 0.022) moles

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of particles

So, 0.022 moles of sodium sulfite will contain = (2\times 0.022\times 6.022\times 10^{23})=2.65\times 10^{22} number of sodium ions

Hence, the number of sodium ions in given amount of sodium sulfite are 2.65\times 10^{22}

  • <u>For b:</u>

Moles of sulfite ions in sodium sulfite = (1 × 0.022) moles

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of particles

So, 0.022 moles of sodium sulfite will contain = (1\times 0.022\times 6.022\times 10^{23})=1.325\times 10^{22} number of sulfite ions

Hence, the number of sulfite ions in given amount of sodium sulfite are 1.325\times 10^{22}

  • <u>For c:</u>

Molar mass of sodium sulfite = 126 g/mol

According to mole concept:

6.022\times 10^{23} number of formula units are present in 1 mole of a compound

Or, 6.022\times 10^{23} number of formula units of sodium sulfite have a mass of 126 grams

So, 1 formula unit of sodium sulfite will have a mass of = \frac{126}{6.022\times 10^{23}}\times 1=2.09\times 10^{-22}g

Hence, the mass of one formula unit of sodium ions is 2.09\times 10^{-22} grams

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