The answer to your question is Hubble’s law
Answer:
20atm
Explanation:
according to boyles law P1V1= P2V2
Answer:
A
Explanation:
Because you need to multiply the length value by 1000
Answer:
The Percent composition of isopropanol in the mixture is 29.07 %
Explanation:
Step 1: Data given
Number of moles isopropanol (C3H8O) = 2.52 moles
Mass of the solution = 521 grams
Molar mass of isopropanol (C3H8O) = 60.1 g/mol
Step 2: Calculate mass of isopropanol
Mass isopropanol = moles isopropanol * molar mass isopropanol
Mass isopropanol = 2.52 moles * 60.1 g/mol
Mass isopropanol = 151.45 grams
Step 3: Calculate the percent composition of isopropanol in the mixture
Percent composition of isopropanol = (mass isopropanol / total mass of mixture) * 100 %
Percent composition of isopropanol = (151.45 grams / 521 grams ) * 100 %
Percent composition of isopropanol = 29.07 %
The Percent composition of isopropanol in the mixture is 29.07 %
Answer: 24.1%, under below assumptions.
Justification:
The question is quite ambiguous, because one of the data is not clearly stated. It says that the mixture consists on two compounds:
- sodium bicarbonate, and
- ammonium bicarbonate
.After, it says that it is 75.9 % bicarbonate, but it does not specify which bicarbonate, it might be the sodium bicarbonate or the ammonium bicarbonate. It is apparent that you omitted that information by error.
Given that later, the question is <span>what the mass percent of sodium bicarbonate is in the mixture, it is supposed that the 75.9% content is of ammonium bicarbonate.
With that said, you can calculate the mass percent of sodium bicarbonate, because there are only two compounds and so you know that both add up the 100% of the mixture.
In formulas:
100% = %m/m sodium bicarbonate + %m/m ammonium bicarbonate = 100%
=> % m/m sodium bicarbonate = 100% - % m/s ammonium bicarbonate
=> % sodium bicarbonate = 100% - 75.9% = 24.1%
Answer: 24.1%
</span>
