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ra1l [238]
2 years ago
11

Please help! Is there another way that 3.40x10^-19J can be imputed on a computer. I have the right answer but it is wrong.

Chemistry
1 answer:
r-ruslan [8.4K]2 years ago
4 0

The energy of the photon with the wavelength of 584 nm is 3.4×10¯¹⁹ J

<h3>How to determine the frequency of the photon</h3>
  • Wavelength (λ) = 584 nm = 584×10⁻⁹ m
  • Speed of light (v) = 3×10⁸ m/s
  • Frequency (f) = ?

f = v / λ

f = 3×10⁸ / 584×10⁻⁹

f = 5.14×10¹⁴ Hz

<h3>How to determine the energy</h3>
  • Planck's constant (h) = 6.626×10¯³⁴ Js
  • Frequency (f) = 5.14×10¹⁴ Hz
  • Energy (E) =?

E = hf

E = 6.626×10¯³⁴ × 5.14×10¹⁴ Hz

E = 3.4×10¯¹⁹ J

Learn more about energy:

brainly.com/question/10703928

#SPJ1

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Answer:

Results from method B is more reliable than method A.

Explanation:

The two method that are used for the analysis produced different results. The first method that is method A  gives higher value of the iodine content than the method B.

When $Mn^{2+}$ was added to water, method A showed an increased in the iodine content and it increases with the increase in the amount of $Mn^{2+}$ .

Where as in the method B, there is no change in the results. Therefore the measurements provided by the method A shows an inference of $Mn^{2+}$ ion.

The measurement of the iodine content is affected by the presence of the ion $Mn^{2+}$ in water.

Since in method B there is no change in measurement, it is independent of the presence $Mn^{2+}$ ion in water.

As higher iodine content is given by method A, so $Mn^{2+}$  ion must be present in original water that must be interfering the measurement. Hence, method B is more reliable.

3 0
3 years ago
How many moles of air are necessary for the combustion of 5.00 molmol of isooctane, assuming that air is 21.0% O2O2 by volume?
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67.5 moles of O2

Explanation:

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8 0
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Answer:

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The energy conversions are never 100 percent efficient. This is because the energy originally is converted into a mixture of the useful and not useful energy. For example, gasoline in the car is converted to motion, sound and friction. The later two (sound and friction) are energies but are less useful. Thus, in this case, the energy conversion is not 100 % efficient. Thus, the energy efficiency equation comes into play. This is given as the ratio of the useful energy to the total energy. It is a fraction.  

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