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ra1l [238]
2 years ago
11

Please help! Is there another way that 3.40x10^-19J can be imputed on a computer. I have the right answer but it is wrong.

Chemistry
1 answer:
r-ruslan [8.4K]2 years ago
4 0

The energy of the photon with the wavelength of 584 nm is 3.4×10¯¹⁹ J

<h3>How to determine the frequency of the photon</h3>
  • Wavelength (λ) = 584 nm = 584×10⁻⁹ m
  • Speed of light (v) = 3×10⁸ m/s
  • Frequency (f) = ?

f = v / λ

f = 3×10⁸ / 584×10⁻⁹

f = 5.14×10¹⁴ Hz

<h3>How to determine the energy</h3>
  • Planck's constant (h) = 6.626×10¯³⁴ Js
  • Frequency (f) = 5.14×10¹⁴ Hz
  • Energy (E) =?

E = hf

E = 6.626×10¯³⁴ × 5.14×10¹⁴ Hz

E = 3.4×10¯¹⁹ J

Learn more about energy:

brainly.com/question/10703928

#SPJ1

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Enter your answer in the provided box. The atomic masses of 63Cu (69.17 percent) and 65Cu (30.83 percent) are 62.94 and 64.93 am
dybincka [34]

<u>Answer:</u> The average atomic mass of copper is 63.55 amu.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

  • <u>For _{29}^{63}\textrm{Cu} isotope:</u>

Mass of _{29}^{63}\textrm{Cu} isotope = 62.94 amu

Percentage abundance of _{29}^{63}\textrm{Cu} = 69.17 %

Fractional abundance of _{29}^{63}\textrm{Cu} isotope = 0.6917

  • <u>For _{29}^{65}\textrm{Cu} isotope:</u>

Mass of _{29}^{65}\textrm{Cu} isotope = 64.93 amu

Percentage abundance of _{29}^{65}\textrm{Cu} = 30.83 %

Fractional abundance of _{29}^{65}\textrm{Cu} isotope = 0.3083

Putting values in equation 1, we get:

\text{Average atomic mass of Copper}=[(62.94\times 0.6917)+(64.93\times 0.3083)]\\\\\text{Average atomic mass of copper}=63.55amu

Hence, the average atomic mass of copper is 63.55 amu.

4 0
3 years ago
Glucose is a simple sugar. It would most likely be found in which of the following foods?
olga55 [171]
It would be most likely to be found in carbohydrates
7 0
3 years ago
Read 2 more answers
What’s the solution?
emmasim [6.3K]

Answer:

See balanced equations below

Explanation:

1. Mg(s) +2 HCL (aq) →MgCl₂ (aq) +H₂(g)

This is a single replacement reaction, involving an acid with a metal

2. 2Al(s) + 3H₂SO₄ (aq)→Al₂(SO₄)₃(aq) + 3H₂

3. 3 Zn (s) + 2H₃PO₄(aq)→ Zn₃(PO₄)₂ (aq) + 3H₂ (g)

4. 2Al(s) + 6HCL (aq)→2AlCl₃(aq) +3H₂ (g)

B.

1. 2KOH(aq) + MgCl₂→Mg(OH)₂ (aq) + 2KCl (aq)

2. 3NaOH (aq)+ Al(NO₃)₃ (aq)→Al(OH)₃(s) + 3 NaNO₃(aq) ---this is a precipitation reaction

3. BaBr₂(aq) + H₂SO₄→BaSO₄ (s) + 2Br⁻(aq)

4. Na₂S + 2HCl → 2NaCl (aq) + H₂S (g)

5. 3CaCl₂ +2K₃PO₄→ Ca₃(PO₄)₂+6KCl

6.Ba(NO₃)₂ + (NH₄)₂CO₃→ 2(NH₄)⁺(aq) +BaCO₃(s)

6 0
3 years ago
GasesToxic fumesParticulates are solid or liquid particles that settle after being dispersed in a gas.
lesantik [10]
I think the correct answer is the third option. Particulates are solid or liquid particles that settle after being dispersed in a gas. They are also termed as particle pollution or PM. It is a mixture of very small particles and liquid droplets which includes acids of nitrates and sulfates, organic substance, metals and dust particles.
6 0
3 years ago
Read 2 more answers
Need help asap!!! (SCIENCE)
balu736 [363]
<h3><u>Answer;</u></h3>

10 percent

<h3><u>Explanation;</u></h3>
  • Probability is a number that describes how likely it is that an event will occur.
  • In this case; If each of 10 events is equally likely to occur, the probability of each individual event occurring is 1/10.
  • Therefore; as a percentage;

1/10 × 100 = 10 percent

  • Hence; The probability of each individual event occurring is 10 percent
6 0
3 years ago
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