How can you predict a child'a height?

If it takes 150N of force to move a box 10 meters. what is the work done on the box?

sergeinik [125]

Answer:

1500 Joules

Explanation:

Work = Force x Distance

When multiplying by 10 you simply shift all the digits to the

left and append a 0 to the end.

so 150 x 10 = 1500 Joules

3 0

3 years ago

Read 2 more answers

What are the rules for setting up an integral of rotation?

Angelina_Jolie [31]

Setting up an integral of rotation is used as a method of of calculating the volume of a 3D object formed by a rotated area of a 2D space. Finding the volume is similar to finding the area, but there is one additional component of rotating the area around a line of symmetry.

<span>First the solid of revolution should be defined. The general function is y=f(x), on an interval [a,b].</span>

Then the curve is rotated about a given axis to get the surface of the solid of revolution. That is the integral of the function.

<span>It all depends of the function f(x), which must be known in order to calculate the integral.</span>

3 0

3 years ago

An 80g meter stick is supported at its 30 cm mark by a string attached to the ceiling. A 20 g mass is hung from the 80 cm mark w

BARSIC [14]

Answer:

$104\; {\rm g}$ , assuming that the meter stick is uniform with the center of mass precisely at the $50\; {\rm cm}$ mark.

Explanation:

Refer to the diagram attached. The meter stick could be considered as a lever. The string at the $30\; {\rm cm}$ mark would then act as the fulcrum of this lever.

The $m_{A} = 20\; {\rm g}$ mass at the $80\; {\rm cm}$ mark is at a distance of $r_{A} = 50\; {\rm cm}$ to the right of the fulcrum at $30\; {\rm cm}$ .

The weight of the $80\; {\rm g}$ meter stick acts like a weight of $m_{B} = 80\; {\rm g}$ attached to the center of mass of this meter stick. Under the assumptions, this center of mass of this meter stick would be at the $50\; {\rm cm}$ mark, which is $r_{B} = 20\; {\rm cm}$ to the right of the fulcrum at $30\; {\rm cm}$ .

Let $m_{C}$ be the mass attached to the meter stick at the $5\; {\rm cm}$ mark. This mass would be at a distance of $r_{C} = 25\; {\rm cm}$ to the left of the fulcrum at $30\; {\rm cm}$ .

At equilibrium:

$\begin{aligned} & m_{C}\, r_{C} && (\text{mass on the left of fulcrum})\\ &= m_{A}\, r_{A} + m_{B} \, r_{B} && (\text{mass on the right of fulcrum})\end{aligned}$ .

Solve for $m_{C}$ , the unknown mass attached to the meter stick at the $5\; {\rm cm}$ mark:

$\begin{aligned}m_{C} &= \frac{m_{A}\, r_{A} + m_{B}\, r_{B}}{r_{C}} \\ &= \frac{20\; {\rm g} \times 50\; {\rm cm} + 80\; {\rm g} \times 20\; {\rm cm}}{25\; {\rm cm}} \\ &= 104\; {\rm g}\end{aligned}$ .

5 0

3 years ago

Which of the following cannot be used for measurement of time

Snowcat [4.5K]

Answer:

D. blinking ofeyea

Explanation:

not really sure

6 0

3 years ago

Which of these statements accurately captures a current trend in operations? A. There is increased focus on local market and lo

Flura [38]

Answer:

Option B

Explanation:

The current trend in operations is accurately captured by Rapid Product Development.

This concept in an organization describes a process in development which is quite fast and progressive.

To achieve rapid Product Development, a combination of integration of various innovative and creative prototyping techniques including latest Computer supportive operative tools, i.e., CSCW are used.

These tools are incorporated into the process of Research and Development in an organization in order to develop products by optimization of quality, price and time.

3 0

3 years ago