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GuDViN [60]
3 years ago
15

A container of water is lifted vertically 3.0m

Physics
1 answer:
Nikitich [7]3 years ago
3 0
It is positive if that's what you are asking.
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1. A huge spool of wire, 10,000 meters long, weighs 81.34 N. You cut off a meter or so and tie it between two posts, 0.660 m apa
WARRIOR [948]

Answer:

The beat frequency is 6.378 Hz.

Explanation:

Given that,

Length of wire = 10000 m

Weight = 81.34 N

Distance = 0.660 m

Tension = 52 N

Frequency = 196 Hz

We need to calculate the mass of the wire

Using formula of weight

W= mg

m = \dfrac{W}{g}

Put the value into the formula

m=\dfrac{81.34}{9.8}

m=8.3\ kg

The mass per unit length of the wire

m_{l}=\dfrac{m}{l}

Put the value into the formula

m_{l}=\dfrac{8.3}{10000}

m_{l}=8.3\times10^{-4}\ kg/m

We need to calculate the frequency in the wire

Using formula of frequency

f_{w}=\dfrac{1}{2l}\sqrt{\dfrac{T}{m_{l}}}

Put the value into the formula

f_{w}=\dfrac{1}{2\times0.660 }\sqrt{\dfrac{52}{8.3\times10^{-4}}}

f_{w}=189.62\ Hz

We need to calculate the beat frequency

Using formula of beat frequency

f_{b}=f_{in}-f_{w}

Put the value into the formula

f_{b}=196-189.622

f_{b}=6.378\ Hz

Hence, The beat frequency is 6.378 Hz.

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2 years ago
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