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nlexa [21]
4 years ago
11

Which statement about kinetic and static friction is accurate?

Physics
1 answer:
vesna_86 [32]4 years ago
6 0

Answer:

Static friction is greater than kinetic friction, but they both act opposite the applied force.

Explanation:

Newton's 3rd law states that every action has and equal but opposite reaction.

If an object has static friction, that means it stays in one spot, and it takes a great amount of force to get it moving.

Once the object is moving it has kinetic friction, but it's easier to keep it moving unless you are trying to stop it.

The equal but opposite reaction to something moving it is stopping it, and the equal but opposite reaction to stopping something is moving it.

The same amount of force used to move/stop something is used to stop/move it.

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A 2.0 kg particle moves in a circle of radius 3.1 m. As you look down on the plane of its orbit, the particle is initially movin
Ghella [55]

Answer

given,

L(t) = 10 - 3.5 t

mass of particle = 2 Kg

radius of the circle = 3.1 m

a) torque

    τ = \dfrac{dL}{dt}

    τ = \dfrac{d}{dt}(10 - 3.5 t)

    τ = -3.5 N.m

Particle rotates clockwise as i look down the plane. Hence, its angular velocity is downward.

L decreases the angular acceleration upward. so, net torque is upward.

b) Moment of inertia of the particle

    I = m R^2

    I = 2 x 3.1²

    I = 19.22 kg.m²

    L = I ω

    ω = \dfrac{L}{I}

    ω = \dfrac{10 - 3.5 t}{19.22}

    ω = 0.520 - 0.182 t

  A = 0.52 rad/s             B = -0.182 rad/s²

5 0
3 years ago
Read 2 more answers
20 points plz help i dont really understand how to do this
Artist 52 [7]

\huge{ \mathfrak{  \underline{ Answer} \:  \:  ✓ }}

1. Calculate the equivalent resistance in the circuit :

In the given diagram, the resistors are in series connection,

So equivalent resistance = sum of resistance of both resistors.

\large \boxed{R_{eq} =R_1 +R_2  }

  • R_{eq} =  480 + 360

  • R_{eq} = 840 \: ohms

Therefore, Equivalent resistance = 840 ohms.

2. Calculate the current through the battery :

\boxed{ \mathrm{current =  \dfrac{potential \:  \: difference}{resistance} }}

  • i =  \dfrac{120}{840}

  • i =  \dfrac{1}{7}

  • i = 0.142 \: Amperes

Hence, current through the battery = 0.142 A

3. How much current is passing through each resistor :

Since the resistors are joined in series connection, the current flowing through each resistor will be equal = 0.142 Amperes.

___________________________

\mathrm{ \#TeeNForeveR}

4 0
3 years ago
Suppose that it takes 0.6 seconds for a mass on a spring to move from its highest position to its lowest position. What is the p
o-na [289]
The mass on the spring is bouncing. 

We would call it a wave-like motion, except that it all stays in the same place.  But, just like a wave, moving from the highest position to the lowest position
is one-half of a full wiggle. 

(The other half consists of moving from the lowest position back up to the
highest position, where it started from. 

So, half of the wave-like motion takes 0.6 seconds. 

A full cycle of the wave motion ... the actual period of the bounce,
is double that much time . . .
                                                   1.2 seconds.
6 0
4 years ago
A force of 50 N stretches a string by 4 cm,calculate the elastic constant.
murzikaleks [220]

Answer:

50/0.04= answer

8 0
3 years ago
I need help in my physics class and show me how it’s done
Korolek [52]

If we have the angle and magnitude of a vector A we can find its Cartesian components using the following formula

A_x = |A|cos(\alpha)\\\\A_y = |A|sin(\alpha)

Where | A | is the magnitude of the vector and \alpha is the angle that it forms with the x axis in the opposite direction to the hands of the clock.

In this problem we know the value of Ax and Ay and we need the angle \alpha.

Vector A is in the 4th quadrant

So:

A_x = 6\\\\A_y = -6.5

So:

|A| = \sqrt{6^2 + (-6.5)^2}\\\\|A| = 8.846

So:

Ay = -6.5 = 8.846cos(\alpha)\\\\sin(\alpha) = \frac{-6.5}{8.846}\\\\sin(\alpha) = -0.7348\\\\\alpha = sin^{- 1}(- 0.7348)

\alpha = -47.28 ° +360° = 313 °

\alpha = 313 °

Option 4.

4 0
3 years ago
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