Answer
given,
L(t) = 10 - 3.5 t
mass of particle = 2 Kg
radius of the circle = 3.1 m
a) torque
τ = 
τ = 
τ = -3.5 N.m
Particle rotates clockwise as i look down the plane. Hence, its angular velocity is downward.
L decreases the angular acceleration upward. so, net torque is upward.
b) Moment of inertia of the particle
I = m R^2
I = 2 x 3.1²
I = 19.22 kg.m²
L = I ω
ω = 
ω = 
ω = 
A = 0.52 rad/s B = -0.182 rad/s²

1. Calculate the equivalent resistance in the circuit :
In the given diagram, the resistors are in series connection,
So equivalent resistance = sum of resistance of both resistors.

Therefore, Equivalent resistance = 840 ohms.
2. Calculate the current through the battery :

Hence, current through the battery = 0.142 A
3. How much current is passing through each resistor :
Since the resistors are joined in series connection, the current flowing through each resistor will be equal = 0.142 Amperes.
___________________________

The mass on the spring is bouncing.
We would call it a wave-like motion, except that it all stays in the same place. But, just like a wave, moving from the highest position to the lowest position
is one-half of a full wiggle.
(The other half consists of moving from the lowest position back up to the
highest position, where it started from.
So, half of the wave-like motion takes 0.6 seconds.
A full cycle of the wave motion ... the actual period of the bounce,
is double that much time . . .
1.2 seconds.
If we have the angle and magnitude of a vector A we can find its Cartesian components using the following formula

Where | A | is the magnitude of the vector and
is the angle that it forms with the x axis in the opposite direction to the hands of the clock.
In this problem we know the value of Ax and Ay and we need the angle
.
Vector A is in the 4th quadrant
So:

So:

So:

= -47.28 ° +360° = 313 °
= 313 °
Option 4.