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sleet_krkn [62]
3 years ago
7

Magnesium is a metal with two elections in its outermost energy level. When it becomes an ion, what happens to its valence elect

ions? What happens to its charge?
Chemistry
1 answer:
Law Incorporation [45]3 years ago
3 0

Answer:

The answer to your question is Mg loses its valence electrons and acquire a positive charge (Mg⁺²).

Explanation:

Valence electrons are important for an element to attach to another one, metals lose these electrons while nonmetals gain electrons to complete the octet rule.

Magnesium is a metal that loses these electrons so when it becomes an ion Magnesium will have a positive charge  Mg⁺².

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larisa86 [58]

Answer:

0.296 J/g°C

Explanation:

Step 1:

Data obtained from the question.

Mass (M) =35g

Heat Absorbed (Q) = 1606 J

Initial temperature (T1) = 10°C

Final temperature (T2) = 165°C

Change in temperature (ΔT) = T2 – T1 = 165°C – 10°C = 155°C

Specific heat capacity (C) =..?

Step 2:

Determination of the specific heat capacity of iron.

Q = MCΔT

C = Q/MΔT

C = 1606 / (35 x 155)

C = 0.296 J/g°C

Therefore, the specific heat capacity of iron is 0.296 J/g°C

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3 years ago
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Answer:

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Explanation:

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2 years ago
The symbol for the element in period 2, group 13
denis-greek [22]
Element: Boron
Symbol: B
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2 years ago
Calculate the change in entropy when 1.00 kg of water at 100 ∘C is vaporized and converted to steam at 100 ∘C. Assume that the h
andrew11 [14]

Answer : The change in entropy is 6.05\times 10^3J/K

Explanation :

Formula used :

\Delta S=\frac{m\times L_v}{T}

where,

\Delta S = change in entropy = ?

m = mass of water = 1.00 kg

L_v = heat of vaporization of water = 2256\times 10^3J/kg

T = temperature = 100^oC=273+100=373K

Now put all the given values in the above formula, we get:

\Delta S=\frac{(1.00kg)\times (2256\times 10^3J/kg)}{373K}

\Delta S=6048.25J/K=6.05\times 10^3J/K

Therefore, the change in entropy is 6.05\times 10^3J/K

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