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exis [7]
4 years ago
9

Can someone help me!

Chemistry
2 answers:
Art [367]4 years ago
5 0

Answer:

A

Explanation:

anzhelika [568]4 years ago
5 0

Answer:

A: joules are the si units for specific heat capacity

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Devon says that acid in your stomach will make you unhealthy. do you agree or disagree. Explain
irakobra [83]

Answer:

I disagree

Explanation:

because you already have acid in your stomach. obviously drinking deadly acid is not healthy lol

6 0
3 years ago
Read 2 more answers
The student collects the H2 (g) produced by the reaction and measures the volume
BARSIC [14]

The question is incomplete, the complete question is;

The student collects the H2(g) produced by the reaction and measures its volume over water at 298 K after carefully equalizing the water levels inside and outside the gas-collection tube, as shown in the diagram below. The volume is measured to be 45.6mL . The atmospheric pressure in the lab is measured as 765 torr , and the equilibrium vapor pressure of water at 298 K is 24 torr .(i) The pressure inside the tube due to the H2(g)

Answer:

741 torr

Explanation:

From the question we can see that the atmospheric pressure in the lab is 765 torr.

The vapour pressure of water = 24 torr

From Dalton's law of partial pressure, we know that;

Total pressure = Pressure of the H2 + Partial pressure of water vapour

Therefore;

Pressure of H2 = Total pressure - Partial pressure of water vapour

Pressure of H2 = 765 torr - 24 torr = 741 torr

7 0
3 years ago
Nuclear fission reactions can produce different radioisotopes. One of these radioisotopes
hichkok12 [17]
Based on the information provided,

The evidence that this nuclear reaction reaction represent transmutation is it formed different elements

hope this helps
7 0
4 years ago
How many liters of water are needed to dissolve 75.0 grams of NaOH to prepare a 1.00-M solution?​
Pepsi [2]

Answer:

About 500

Explanation:

Bc i used my calc

4 0
3 years ago
A 47.1 g sample of a metal is heated to 99.0°C and then placed in a calorimeter containing 120.0 g of water (c = 4.18 J/g°C) at
wlad13 [49]

Answer : The metal used was iron (the specific heat capacity is 0.44J/g^oC).

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

C_1 = specific heat of metal = ?

C_1 = specific heat of water = 4.18J/g^oC

m_1 = mass of metal = 47.1 g

m_2 = mass of water = 120 g

T_f = final temperature of water = 24.5^oC

T_1 = initial temperature of metal = 99^oC

T_2 = initial temperature of water = 21.4^oC

Now put all the given values in the above formula, we get

47.1g\times c_1\times (24.5-99)^oC=-120g\times 4.18J/g^oC\times (24.5-21.4)^oC

c_1=0.44J/g^oC

Form the value of specific heat of metal, we conclude that the metal used in this was iron.

Therefore, the metal used was iron (the specific heat capacity is 0.44J/g^oC).

3 0
3 years ago
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