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valentinak56 [21]
3 years ago
8

A ray of light passes from air into

Physics
1 answer:
Nata [24]3 years ago
3 0
The frequency doesn't change as the wave crosses
the boundary between one medium and another.
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In order to get going fast, eagles will use a technique called stooping, in which they dive nearly straight down and tuck in the
polet [3.4K]

Answer:

the anwser is The healthy adult golden eagle, due to its impressive size and hunting prowess, has no natural predators. Eggs, chicks, immature eagles, and injured birds are susceptible to a range of predators, such as other birds of prey, including other kinds of eagles and hawks, bears, wolves and cougars.

Explanation:

7 0
4 years ago
Read 2 more answers
What is the number “4” in SiCl4? a subscript a coefficient a product a reactant
Svetlanka [38]

Answer: 4 is the subscript in SiCl_{4}.

Explanation:

We know that,

Subscript: The number of atom present in a given compound.

In SiCl_{4}, 4 represents the number of chlorine atom in 1 mole of Silicon tetra chloride.

Coefficient: Number of atom which is used in reaction.

For example: In 3SiCl_{4}, 3 is the coefficient of silicon tetra chloride.

A Product : In the balance equation, right hand side is called product.

A reactant : In the balance equation, left hand side is called reactant.

For example: the balance equation is

2Mg+O_{2}\rightarrow 2MgO

In this equation, 2Mg+O_{2} is the reactants and 2MgO is products.

Hence, 4 is the subscript in SiCl_{4}.

4 0
3 years ago
Read 2 more answers
I need help ASAP PLEASE!!!
Setler79 [48]

Answer:

A. O and Fe

Explanation:

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3 0
3 years ago
A 2.00 kg, frictionless block s attached to an ideal spring with force constant 550 N/m. At t = 0 the spring is neither stretche
gladu [14]

Answer:

a)    A = 0.603 m , b) a = 165.8 m / s² , c)  F = 331.7 N

Explanation:

For this exercise we use the law of conservation of energy

Starting point before touching the spring

    Em₀ = K = ½ m v²

End Point with fully compressed spring

    Em_{f} = K_{e} = ½ k x²

    Emo = Em_{f}

    ½ m v² = ½ k x²

    x = √(m / k)    v

    x = √ (2.00 / 550)   10.0

    x = 0.603 m

This is the maximum compression corresponding to the range of motion

     A = 0.603 m

b) Let's write Newton's second law at the point of maximum compression

    F = m a

    k x = ma

    a = k / m x

    a = 550 / 2.00 0.603

    a = 165.8 m / s²

With direction to the right (positive)

c) The value of the elastic force, let's calculate

    F = k x

    F = 550 0.603

   F = 331.65 N

5 0
3 years ago
A scientist testing to see how a cat “always” lands on their feet drops a cat upside down out of a third story window at a heigh
makkiz [27]

<u>Answer: </u>

Cat has 2.02 seconds to right itself.

<u>Explanation: </u>

Initial height of cat from ground = 20 meter.

We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this the velocity of cat in vertical direction = 0 m/s, acceleration = acceleration due to gravity =  9.8 m/s^2, we need to calculate time when s = 20 meter.

Substituting

20=0*t+\frac{1}{2} *9.8*t^2\\ \\ t = 2.02 seconds

So, cat has 2.02 seconds to right itself.

7 0
3 years ago
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