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Reil [10]
2 years ago
14

What are the three parts of the power phase? *

Physics
1 answer:
brilliants [131]2 years ago
6 0

Answer:

body position

Mid-Pull

Glide

Explanation:

umm

this is so simple

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Oil, natural gas, nuclear, and coal are all examples of _______________
cluponka [151]

Non-Renewable Resources.

8 0
2 years ago
What is the speed that is measured in speedometer to track speed violation?
BartSMP [9]

Answer:

The officer's unit detects this 135-mile-per-hour speed and should subtract the patrol car's 70-mile -per-hour ground speed to get your true speed of 65 miles per hour. Instead, the officer's ground-speed beam fixes on the truck ahead and measures a false 50-mile-per-hour ground speed.

Explanation:

A speedometer or speed meter is a gauge that measures and displays the instantaneous speed of a vehicle. Now universally fitted to motor vehicles, they started to be available as options in the early 20th century, and as standard equipment from about 1910 onwards.

4 0
3 years ago
Bacteria prefer a dry environment to a damp or moist environment. False True
mariarad [96]

Answer:

false

Explanation:

cause bacteria prefers moist and damp environment

7 0
3 years ago
Read 2 more answers
Spacetime interval: What is the interval between two events if in some given inertial reference frame the events are separated b
shepuryov [24]

Answer:

  • a. \Delta s ^2 = 8.0888 \ 10^{17} m^2
  • b. \Delta s ^2 = 3.0234 \ 10^{16} m^2
  • c. \Delta s ^2 = 3.0234 \ 10^{20} m^2

Explanation:

The spacetime interval \Delta s^2 is given by

\Delta s ^2 = \Delta (c t) ^ 2 - \Delta \vec{x}^2

please, be aware this is the definition for the signature ( + - - - ), for the signature (- + + + ) the spacetime interval is given by:

\Delta s ^2 = - \Delta (c t) ^ 2 + \Delta \vec{x}^2.

Lets work with the signature ( + - - - ), and, if needed in the other signature, we can multiply our interval by -1.

<h3>a.</h3>

\Delta \vec{x}^2 = (7.5 \ 10 \ m)^2

\Delta \vec{x}^2 = 5,625 m^2

\Delta (c t) ^ 2 = (299,792,458 \frac{m}{s} \ 3 \ s)^2

\Delta (c t) ^ 2 = (899,377,374 \ m)^2

\Delta (c t) ^ 2 = 8.0888 \ 10^{17} m^2

so

\Delta s ^2 = 8.0888 \ 10^{17} m^2 - 5,625 m^2

\Delta s ^2 = 8.0888 \ 10^{17} m^2

<h3>b.</h3>

\Delta \vec{x}^2 = (5 \ 10 \ m)^2

\Delta \vec{x}^2 = 2,500 m^2

\Delta (c t) ^ 2 = (299,792,458 \frac{m}{s} \ 0.58 \ s)^2

\Delta (c t) ^ 2 = (173,879,625.6 \ m)^2

\Delta (c t) ^ 2 = 3.0234 \ 10^{16} m^2

so

\Delta s ^2 = 3.0234 \ 10^{16} m^2 - 2,500 m^2

\Delta s ^2 = 3.0234 \ 10^{16} m^2

<h3>c.</h3>

\Delta \vec{x}^2 = (5 \ 10 \ m)^2

\Delta \vec{x}^2 = 2,500 m^2

\Delta (c t) ^ 2 = (299,792,458 \frac{m}{s} \ 58 \ s)^2

\Delta (c t) ^ 2 = (1.73879 \ 10^{10} \ m)^2

\Delta (c t) ^ 2 = 3.0234 \ 10^{20} m^2

so

\Delta s ^2 = 3.0234 \ 10^{20} m^2 - 2,500 m^2

\Delta s ^2 = 3.0234 \ 10^{20} m^2

5 0
2 years ago
What pushes against gravity in: a main sequence star, a white dwarf, a neutron star, and a black hole? electron degeneracy, neut
Inga [223]

Answer:

heat pressure, electron degeneracy, neutron degeneracy, and nothing

Explanation:

Main Sequence Star: It is a star in which nuclear fusion is happening in the core of the star. Hydrogen molecules fuse together to generate Helium. This nuclear fusion generates outward gas pressure and radiation pressure which balances the inward gravity thus creating an equilibrium which keeps the stars in shape.

White dwarf: It is the end stage of a medium sized star like the Sun. Outer layers of the star are thrown in the form a shell/bubble leaving a small and dense core in the center called as white dwarf. This core consists of carbon and oxygen. Nuclear fusion doesn't occur in the core of white dwarfs. The inward gravity is balanced by the electron degeneracy pressure. Thus these stars will keep on radiating the remaining heat and will turn in to a black dwarf at the end.

Neutron Star: This is the end stage of a supermassive star (1-3 times the mass of the Sun). At the last stage of the life the core collapses. In these stars the inward gravity is so huge that the pressure overcomes the electron degeneracy pressure and crushes together the electron and proton to form neutron. The neutron then stops the collapse and balances the inward gravity.

Black Hole: This is the end stage of a hyper massive stars weighing more than 3 times the mass of the Sun. The inward gravitational force is so huge that even the neutrons are not able to stop the collapse the core. thus the mass of the star collapses into a very small area of immense gravity. There is nothing that can balance this inward gravity.

3 0
2 years ago
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