6. Balsa wood with an average density of 130 kg/m3 is floating in pure water. What percentage of the wood is submerged

Physics

1 answer:

yaroslaw [1]3 years ago

8 0

Answer:

The percentage of the submerged wood is 13%.

Explanation:

Given;

density of the Balsa wood, $\rho _{wood}$ = 130 kg/m³

density of pure water, $\rho_{water}$ = 1000 kg/m³

The percentage of the submerged wood is calculated as;

$Percentage \ of \ submerged \ wood = \frac{130 \ kg/m^3}{1000 \ kg/m^3} \ \times \ 100 \% \\\\Percentage \ of \ submerged \ wood = 13 \ \%$

Therefore, the percentage of the submerged wood is 13%.

You might be interested in

A ball that has a mass of 0.25 kg spins in a circle at the end of a 1.6 m rope. the ball moves at a tangential speed of 12.2 m/s

NARA [144]

The centripetal force acting on the ball will be 23.26 N.The direction of the centripetal force is always in the path of the center of the course.

<h3>What is centripetal force?</h3>

The force needed to move a body in a curved way is understood as centripetal force. This is a force that can be sensed from both the fixed frame and the spinning body's frame of concern.

The given data in the problem is;

m is the mass of A ball = 0.25 kg

r is the radius of circle= 1.6 m rope

v is the tangential speed = 12.2 m/s

$\rm F_C$ is the centripetal force acting on the ball