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Natasha_Volkova [10]
3 years ago
9

6. Balsa wood with an average density of 130 kg/m3 is floating in pure water. What percentage of the wood is submerged

Physics
1 answer:
yaroslaw [1]3 years ago
8 0

Answer:

The percentage of the submerged wood is 13%.

Explanation:

Given;

density of the Balsa wood, \rho _{wood}  = 130 kg/m³

density of pure water, \rho_{water} = 1000 kg/m³

The percentage of the submerged wood is calculated as;

Percentage \ of \ submerged \ wood = \frac{130 \ kg/m^3}{1000 \ kg/m^3} \ \times  \ 100 \% \\\\Percentage \ of \ submerged \ wood = 13 \ \%

Therefore, the percentage of the submerged wood is 13%.

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Astronomers discover a bright X-ray source in the Milky Way. They see no counterpart in the optical bands, but it has another st
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Answer:

a. a black hole

Explanation:

X-ray emission from the central degrees of the Milky Way Bright X-ray emission traces the coherent edge brightened shell-like feature, dubbed the northern chimney, located north of Sgr A* and characterized by a diameter of about 160 pc. On the opposite side, the southern chimney appears as a bright linear feature. Bright X-ray emission is observed at high latitude

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HELP!!
tresset_1 [31]

Answer:

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Increasing the amount of current that flows through a wire ______ the strength of an electromagnet
Anestetic [448]

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and the magnetic field due to solenoid is given as

B = \mu_0 n i

here

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so when we increase the current in electromagnet the magnetic field of the solenoid will increase

this will increase the strength of the electromagnet

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Where does the kinetic energy come fromwhen you roll down a hill?
Lapatulllka [165]
From the change of GPE into KE. Conservation of energy tells us this.
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4 years ago
A force of 960 newtons stretches a spring 4 meters. A mass of 60 kilograms is attached to the end of the spring and is initially
Drupady [299]

Answer:

x(t) = - 6 cos 2t

Explanation:

Force of spring = - kx

k= spring constant

x= distance traveled by compressing

But force = mass × acceleration

==> Force = m × d²x/dt²

===> md²x/dt² = -kx

==> md²x/dt² + kx=0   ------------------------(1)

Now Again, by Hook's law

Force = -kx

==> 960=-k × 400

==> -k =960 /4 =240 N/m

ignoring -ve sign k= 240 N/m

Put given data in eq (1)

We get

60d²x/dt² + 240x=0

==> d²x/dt² + 4x=0

General solution for this differential eq is;

x(t) = A cos 2t + B sin 2t   ------------------------(2)

Now initially

position of mass spring

at time = 0 sec

x (0) = 0 m

initial velocity v= = dx/dt=  6m/s

from (2) we have;

dx/dt= -2Asin 2t +2B cost 2t = v(t) --- (3)

put t =0 and dx/dt = v(0) = -6 we get;

-2A sin 2(0)+2Bcos(0) =-6

==> 2B = -6

B= -3

Putting B = 3 in eq (2) and ignoring first term (because it is not possible to find value of A with given initial conditions) - we get

x(t) = - 6 cos 2t

==>  

4 0
3 years ago
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