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2 years ago

6. Balsa wood with an average density of 130 kg/m3 is floating in pure water. What percentage of the wood is submerged

Physics

1 answer:

yaroslaw [1]2 years ago

8 0

Answer:

The percentage of the submerged wood is 13%.

Explanation:

Given;

density of the Balsa wood, $\rho _{wood}$ = 130 kg/m³

density of pure water, $\rho_{water}$ = 1000 kg/m³

The percentage of the submerged wood is calculated as;

$Percentage \ of \ submerged \ wood = \frac{130 \ kg/m^3}{1000 \ kg/m^3} \ \times \ 100 \% \\\\Percentage \ of \ submerged \ wood = 13 \ \%$

Therefore, the percentage of the submerged wood is 13%.

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Twenty grams of a solid at 70°C is place in 100 grams of a fluid at 20°C. Thermal equilibrium is reached at 30°C.

zaharov [31]

Answer:

c. is more than that of the fluid.

Explanation:

This problem is based on the conservation of energy and the concept of thermal equilibrium

$heat= m s \Delta T
$

m= mass

s= specific heat

\DeltaT=change in temperature

let s1= specific heat of solid and s2= specific heat of liquid

then

Heat lost by solid= $20(s_1)(70-30)=800s_1
$

Heat gained by fluid= $100(s_2)(30-20)=1000s_2
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Now heat gained = heat lost

therefore,

1000 S_2=800 S_1

S_1=1.25 S_2

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Answer:

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eimsori [14]

Answer:

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Explanation:

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