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VARVARA [1.3K]
3 years ago
13

Which part of a database is organized most like a spreadsheet, with rows and columns? A. A form B. A report C. A table D. A fiel

d
Business
2 answers:
Gala2k [10]3 years ago
7 0

Answer: C. A table

Explanation:

In a relational database the most important component is the table which contains information arranged in rows and columns. These tables are like sheets found in a spreadsheet. The rows each contain a record while the columns represent a field of data. The rows intersect with a column to form a cell, which is similar to cells found in a spreadsheet. Each record in the database has a unique identifier, similar to how rows are identified by a number in a spreadsheet.

Mariulka [41]3 years ago
6 0

The answer is C. A Table. A Table is an arrangement of information using rows and columns to further organize the information.

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How much total depreciation and amortization expense did Patnode record during 2015?
Oxana [17]

Answer:

d. $5,000

Explanation:

Patnode's information is missing, so I looked it up. I found the balance sheet for 2014 and 2015. Hope that it is the same question:

total depreciation expense for 2015 = change in accumulated depreciation (2015 - 2014) + change in accumulated amortization (2015 - 2014) = ($3,000 - $0) + ($3,000 - $1,000) = $3,000 + $2,000 = $5,000

3 0
3 years ago
Walmart has developed a sophisticated inventory management and cost control system that allows rapid price changes for each prod
finlep [7]

Answer:

A. Radio Frequency Identification

Explanation:

The use of radio frequency identification is to ensure a timely identification of people or objects.

The technology uses radio waves to identify people or objects. There is a device that will be used to read information contained in a wireless device or tags from a distance without making physical contact or requiring a line of sight.

6 0
3 years ago
On May 3, 2017, Leven Corp. negotiated a short-term loan of $685,000. The loan is due October 1, 2017, and carries a 6.86% inter
Semmy [17]

Answer:

704076 $

Explanation:

Exact statement of the question is:

<em>May 3, 2007, Leven Corp. negotiated a short-term loan of $685,000. The loan is due October 1, 2007, and carries a 6.86% interest rate. Use ordinary interest to calculate the interest. What is the total amount Leven would pay on the maturity date? (Round your answer to 2 decimal places. Omit the "$" sign in your response.)</em>

Solution:

Fro 3rd May to October 1st. 2017 there are 151 days

But 365 days = 1 year

==> 151 days = 151× 1/365 =0.414 years

But we use 1 year as one term

==> 1year = 1T

==>  T = 0.414

R= 6.86

P= 685000

A=?

We use formula for the term:

A= P(1+ \frac{R}{100} )^{T}

Where A= ammount at the end of term

P= Loan amount

R= Rate of interest

T= No. of terms

Putting values in this formula;

==> A= 685000×(1+\frac{6.86}{100}) ^{0.414}

==> A= 685000 × 1.02784938489=704076 $

6 0
3 years ago
Leas Corporation staffs a helpline to answer questions from customers. The costs of operating the helpline are variable with res
Nikolay [14]

Answer:

The average cost of operating the helpline per call at a volume of 25,300 calls in a month will be $18.10

Explanation:

The costs of operating the helpline are variable with respect to the number of calls in a month. At a volume of 25,000 calls in a month, the costs of operating the helpline total $452,500.

The average cost of operating the helpline per call = $452,500/25,000 = $18.10

At a volume of 25,300 calls in a month, The average cost of operating the helpline per call does not change but the total costs of operating the helpline increase because the costs of operating the helpline are variable.

Total costs of operating the helpline = $18.10 x 25,300 = $457,930

7 0
3 years ago
Farrell wants to retire in six years. To have sufficient assets to fund retirement, Farrell needs to accumulate an additional $4
Mademuasel [1]

Answer:

$73,070.5

Explanation:

Inflation erodes the value of money. It makes more quantity of money to required to buy the same basket of food and services in the future.

With inflation, to calculate the the quantity of Dollars needed in n years time, we use the formula;

Inflated amount = h × (1 + f)^n

h= amount required today, f - inflation rate, n- number of years

So if Farrell needs $400,000 in 6 years time in real terms, with an inflation of 5% per year, he would need to have a quantity of money equal to

1.05^6 × 400,000 = $536,038.3.

To provide for $536,038.3  in 6 years time, he would need to contribute into a sinking fund on a yearly basis, an equal amount denoted as "A" in the formula below:

FV = A ×  ((1+r)^n  - 1)/r

FV - 536,038.3, r - 8%, n = 6

536,038.3 = A × ((1+0.08 )^(6) - 1)/0.08)

536, 038.3 = A × 7.3359

536,038.3/7.3359 = A

$73,070.5  = A

Farrell should invest at the end of every year

$73,070.5

7 0
3 years ago
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