Where is the centre of mass of a uniform cube located?

How do we know the sun is supported by nuclear fusion?

Leya [2.2K]

we know that the sun is supported by nuclear fusion because the sun is a main-sequence star, meaning it has to use nuclear fusion to keep itself going, no nuclear fusion, no sun.

i hope this helps!

3 0

4 years ago

The laboratory exercise for this chapter addresses kinematic motion. You have experienced these motions in everyday life. Instea

ki77a [65]

Answer:

A) vectors: veloicty, force

scalar: speed, work

B) t = 1.75 s, C) v = - 17 2 m / s

Explanation:

We answer each part separately

A) A vector magnitude has magnitude and direction instead a scalar magnitude has only magnitude

vector quantities: the speed of a car number is the magnitude and direction is where it goes

Force, the number is the magnitude and above that applies gives direction

Scalar magnitude: how quickly the number of the speedometer of the car

Temperature, work

B) I = 15 m height to the soil and get to calculate time = 0

y = y₀ + v₀ t - ½ g t²

as the ball is loose its initial velocity is zero

0 = 0 +0 - ½ g t²

t = $\sqrt{2y_o/g}$

t = $\sqrt{2 \ 15/ 9.8}$

t = 1.75 s

C) the velocity to the reach the floor

v = vo - g t

v = 0 - g t

v = - 9.8 1.74

v = - 17 2 m / s

The negative signt iindicates that the speed goes down

5 0

3 years ago

After touchdown a fighter jet passes a marker on the runway at an instantaneous speed of 100 m/s and constant negative accelerat

daser333 [38]

Given that,

Deacelectration = -15 m/s²

Negative sign shows the declaration

Slowly speed = 25 m/s

Acceleration = 35 m/s²

Speed = 170 m/s

We need to calculate the time

Using equation of motion

$v=u+at$

Where, v = final velocity

u = initial velocity

a = acceleration

t = time

Put the value into the formula

$25=0+15\times t$

$t=\dfrac{25}{15}$

$t=1.66\ sec$

We need to calculate the distance from the original runway

Using equation of motion

$s=ut+\dfrac{1}{2}at^2$

$s=0+\dfrac{1}{2}\times35\times(1.66)^2$

$s=48.2\ m$

Hence, The distance from the original runway is 48.2 m.

3 0

4 years ago

A scooter is moving with a speed of 18 m/s. Its mass is 20 kg. What is the

kykrilka [37]

A scooter is moving with a speed of 18 m/s. Its mass is 20 kg. What is the magnitude of its momentum?

A. 360 kg.m/s

B. 2 kg.m/s

C. 3600 kg.m/s

D. 1.1 kg.m/s

<h3>Given:-</h3>

Speed (v) of a scooter = 18 m/s

Mass (m) = 20 kg

Magnitude of its momentum (p) = ?

<h3>Answer:-</h3>

Since, we know that,

p = mv

So,

p = 20 kg × 18 m/s

p = 360 kg.m/s

<h3> $\therefore$ The correct option is (A) 360 kg.m/s </h3>

<h3>The magnitude of its momentum is <u>3</u><u>6</u><u>0</u><u> </u><u>k</u><u>g</u><u>.</u><u>m</u><u>/</u><u>s</u>. [Answer]</h3>

4 0

3 years ago

A small mass m on a string is rotating without friction in a circle. The string is shortened by pulling it through the axis of r

Komok [63]

I’m not sure, is there any other words you can explain it in ..?

4 0

3 years ago

Where is the centre of mass of a uniform cube located?​

Where is the centre of mass of a uniform cube located?