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grandymaker [24]
3 years ago
14

Identify the atom that is oxidized, reducing agent, in the following equation: Zn(s) + H2SO4(aq) --> ZnSO4(aq) + H2(g)

Chemistry
1 answer:
Sav [38]3 years ago
5 0

Answer:

The atom that is oxidized is Zn.

Explanation:

Reducing agents reduce other atoms or species by being oxidized themselves. Oxidation is a loss of electrons. In the equation, the Zn atom originally has an oxidation state of zero (neutral). On the right side of the equation, Zn is part of the ionic compound zinc sulfate, which is composed of the Zn(2+) cation and the SO4(2-) anion. The Zn(2+) ion is positive, which means it must have lost electrons (which have a negative charge), and was therefore oxidized from the neutral atom Zn(s).

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Whitepunk [10]

Answer:

A

Explanation:

Cuz the when you pair Li and Cl, it becomes LiCl (it has 1:1 ratio)

4 0
3 years ago
Read 2 more answers
How many liters are there in 28g of B?
Juliette [100K]
Hi
The volume is 58.1
The moler mass is 10.8
Molar mass details
10.81B (1*10.81)

Hope this helps
5 0
3 years ago
Which of the following compounds will undergo an Sn2 reaction most readily?
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4 0
3 years ago
Consider the nuclear equation below. Superscript 235 subscript 92 upper U right arrow superscript 4 subscript 2 upper H e. What
Leto [7]

Answer: The nuclide symbol of X is ^{231}_{90}\textrm{Th}

Explanation:

The given nuclear reaction is a type of alpha decay process. In this process, the nucleus decays by releasing an alpha particle. The mass number of the nucleus is reduced by 4 units and atomic number is also decreased by 2 units. The particle released is a helium nucleus.

The general equation representing alpha decay process is:

_{Z}^{A}\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\textrm{He}

For the given equation :

^{235}_{92}\textrm{U}\rightarrow ^{A}_{Z}\textrm{X}+^4_2\textrm{He}

As the atomic number and mass number must be equal on both sides of the nuclear equation:

^{235}_{92}\textrm{U}\rightarrow ^{231}_{90}\textrm{Th}+^4_2\textrm{He}

Thus the nuclide symbol of X is ^{231}_{90}\textrm{Th}

5 0
3 years ago
4.Calculate the volume of 40g of Helium (He) at rtp.
Oksana_A [137]

Answer:

2.24dm³

Explanation:

Given parameters:

Mass of He = 40g

Unknown:

Volume of Helium  = ?

Solution:

To solve this problem, we convert the given mass to number of moles.

   Number of moles  = \frac{mass}{molar mass}  

   molar mass of He  = 4g/mol

  Number of moles  = \frac{4}{40}   = 0.1mole

So;

                  1 mole of gas at rtp occupies a volume of 22.4dm³

                0.1 mole of He will occupy a volume of 0.1 x 22.4 = 2.24dm³

4 0
3 years ago
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