4 C₃H₅(NO₃)₃(l) = 12 CO₂(g) + 6 N₂<span>(g) + 10 H</span>₂O(g) + O₂<span>(g)
4 x ( 227.0995 ) g ---------------> 10 x ( 18.0158) g
mass of </span><span>nitroglycerin-------------> 120 g
</span>m ( nitroglycerin ) = 120 x 4 x 227.0995 / 10 x <span>18.0158
</span>
m ( <span>nitroglycerin ) = 109007.76 / 180.158
m ( </span>nitroglycerin ) = 605.06 g
hope this helps!
Answer:
It's 120 g
Explanation:
I'm doing that question on ck12 and it's correct.
In a longitudinal wave, the motion of the medium is parallel to the direction of the wave. The motion on a transverse wave is perpendicular.
Yup you right homie free young boy