Answer: A. The compound CuCl is 500 times less soluble in sea water than it is in pure water.
pure water.
Explanation:
Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.
This principle states that if there is any change in a equilibrium reaction, the equilibrium will shift in a direction so as to minimize the effect.
Thus when a common ion is introduced to an equilibrium reaction, the equilibrium will shift in a direction where the concentration of common ion is decreasing.
When common ion such as 
from NaCl in sea water is introduced to an equilibrium reaction, the equilibrium will shift in a direction where the concentration of common ion is decreasing i.e. in the left side and thus solubility of CuCl further decreases.
Answer:
C. A neutron turns into a proton
D. An electron is ejected from the nucleus
Explanation:
- Beta decay is a type of the three major types of decays, others being alpha decay and gamma decay.
- During a beta decay the atomic number of an atom increases by one while the mass number remains the same.
- Beta decay may be classified as; an electron emission, positron emission and electron capture.
- <em><u>During electron emission an energetic electron is emitted from the nucleus, together with an antineutrino and a neutron in the nucleus turns into a proton. </u></em>
The total number of matchbooks required would 5,000 be and the cost would be $144
<h3>Mathematical ratios</h3>
50 matchbooks = $1.44
Each matchbook = 0.005 grams red phosphorus
25 grams of red phosphorus is needed:
25/0.005 = 5,000 matchbooks
5,000 matchbooks will cost:
5000/50 x 1.44 = $144
More on mathematical ratios can be found here: brainly.com/question/20387079
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In science you want to use observations and measurements.
Answer:
Explanation:1) ΔrH = 2mol·ΔfH(NO) - (ΔfH(O₂) + ΔfH(N₂)).
ΔrH = 2 mol · 90.3 kJ/mol - (0 kJ/mol + 0 kJ/mol).
ΔrH = 180.6 kJ.
2) ΔS = 2mol·ΔS(NO) - (ΔS(O₂) + ΔS(N₂)).
ΔS = 2mol · 210.65 J/mol·K - (1mol · 205 J/mol·K + 1 mol · 191.5 J/K·mol).
ΔS = 24.8 J/K.
3) ΔG = ΔH - TΔS.
55°C: ΔG = 180.6 kJ - 328.15 K · 24.8 J/K = 172.46 kJ.
2570°C: ΔG = 180.6 kJ - 2843.15 K · 24.8 J/K = 110.09 kJ.
3610°C: ΔG = 180.6 kJ - 3883.15 K · 24.8 J/K = 84.29 kJ.
