Answer:
<u>89.6 L</u>
Explanation:
In normal conditions,
<u><em>For every </em></u><u><em>1 mole</em></u><u><em> of carbon dioxide at STP, it occupies </em></u><u><em>22.4 L</em></u><u><em> of volume.</em></u>
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Solving :
⇒ 1 mole : 22.4 L
⇒ 1 × 4 : 22.4 × 4
⇒ 4 moles : <u>89.6 L</u>
Answer:u would have 40
Explanation:
because ur taking them away
Answer:
49.4 mol Oxygen
Explanation:
Mg(NO3)2 ----- 6 O
1 mol 6 mol
8.24 mol x mol
x = 8.24*6/1 = 49.44 mol ≈ 49.4 mol Oxygen