Question

In the balanced equation, 4ko₂+2co₂→2k₂co₃+30₂ which two chemicals have a molar ratio of 4:3

Answer 1

Answer:

KO₂ and O₂  have 4:3 molar rato

Explanation:

Reaction Given

                  4KO₂+2CO₂→2K₂CO₃+3O₂

chemicals have a molar ratio of 4:3 = ?

Solution

First look at the Reaction

                     4KO₂ + 2CO₂-------→ 2K₂CO₃ + 3O₂

write the moles of the reactant and products that involve

                       4KO₂ + 2CO₂ -------→  2K₂CO₃ + 3O₂

                       4 mol    2 mol               2 mol      3 mol

So the coefficients shows the number of moles of that compound involve in the reaction,

if we look for each ratio of moles to other

• 4 moles of KO₂ : 2 moles of CO₂

So the  molar ratio of KO₂ to CO₂  is 4: 2

• 4 moles of KO₂ : 2 moles of K₂CO₃

So the  molar ratio of KO₂ to K₂CO₃  is 4 : 2

• 2 moles of CO₂ : 2 moles of K₂CO₃

So the  molar ratio of CO₂ to K₂CO₃  is 4 : 2

• 4 moles of KO₂ : 3 moles of O₂

So the molar ratio of KO₂ to O₂  is 4: 3

It is clear that KO₂ and O₂ are the chemicals in this reaction that are in the 4:3 molar ratio