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marta [7]
3 years ago
6

Determine the pH of 1.0 x 10-10M NaOH pH=

Chemistry
1 answer:
Mrrafil [7]3 years ago
7 0

Answer:

4

Explanation:

Applying,

pH = 14-pOH.................... Equation 1

But,

pOH = -log(OH⁻)

Where OH⁻ = Hydroxyl ion concentration of NaOH.

From the question,

Given: OH⁻ = (1×10⁻¹⁰) M

Substitute these values into equation 1

pH = 14-log((1×10⁻¹⁰)

pH = 14-10

pH = 4

Hence the pH of NaOH with a molarity of 1.0 x 10-10M = 4

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A 248-g piece of copper is dropped into 390 mL of water at 22.6 °C. The final temperature of the water was measured as 39.9 °C.
max2010maxim [7]

Answer:

The answer to your question is: Initial temperature of copper = 67.1°C

Explanation:

Data

mass Copper = 248 g

volume Water = 390 ml

T1 water = 22.6°C

T2           = 39.9°C

T1 copper = ?

Specific heat water = 1 cal/g°C

Specific heat copper = 0.092 cal/g°C

Formula       copper             water

Heat is negative for copper because it releases heat

                  - mCp(T2 - T1) = mCp(T2 - T1)                  

                  - (248)(39.9 - T1) = 390 (1)((39.9 - 22.6)           Substitution

                 -9895.2 + 248T1 = 390(17.3)                             Simplification

                 -9895.2 + 248T1 = 6747

                 248 T1 = 6747 + 9895.2

                 248 T1 = 16642.2

                 T1 = 16642.2 / 248

                 T1 = 67.1 °C                                                         Result

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