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zysi [14]
3 years ago
12

If the amplitude of a wave is 4 feet, what is the Wave Height?

Physics
2 answers:
Alexus [3.1K]3 years ago
5 0

A wave is a disturbance that moves along a medium from one end to the other. If one watches an ocean wave moving along the medium (the ocean water), one can observe that the crest of the wave is moving from one location to another over a given interval of time. The crest is observed to cover distance. The speed of an object refers to how fast an object is moving and is usually expressed as the distance traveled per time of travel. In the case of a wave, the speed is the distance traveled by a given point on the wave (such as a crest) in a given interval of time. In equation form,

Vesnalui [34]3 years ago
3 0

Explanation :

The height of the wave is defined as the elevation of the crest minus the elevation of the trough.

or

The wave height is defined as the twice of the amplitude.

It is given that the amplitude of the wave is 4 feet. The height of the wave is given as :

H=2a

Where a is the amplitude of the wave.

So, H = 8 feet.

Hence, this is the required solution.

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rusak2 [61]

Answer:

1. 100 CE

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5. 384 BCE - 322 BCE

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7. 585 BCE

Media and Lydia went into battle and broke off immediately as a result an entire eclipse of the sun which occurred causing the two armies to create peace. The eclipse was already predicted by Thales of Miletus.

8. 585 BCE

Thales of Miletus lived during now.

Explanation:

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7 0
3 years ago
Ratio of resistances of two bulbs is 2:3. If they are connected in series to a supply, then the ratio of voltages across them is
V125BC [204]

Answer:

Explanation:

Given that,

Two resistor has resistance in the ratio 2:3

Then,

R1 : R2 = 2:3

R1 / R2 =⅔

3 •R1 = 2• R2

Let R2 = R

Then,

R1 = ⅔R2 = 2/3 R

So, if the resistor are connected in series

Let know the current that will flow in the circuit

Series connection will have a equivalent resistance of

Req = R1 + R2

Req = R + ⅔ R = 5/3 R

Req = 5R / 3

Let a voltage V be connect across then, the current that flows can be calculated using ohms law

V = iR

I = V/Req

I = V / (5R /3)

I = 3V / 5R

This the current that flows in the two resistors since the same current flows in series connection

Now, using ohms law again to calculated voltage in each resistor

V= iR

For R1 = ⅔R

V1 =i•R1

V1 = 3V / 5R × 2R / 3

V1 = 3V × 2R / 5R × 3

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For R2 = R

V2 = i•R2

V2 = 3V / 5R × R

V2 = 3V × R / 5R

V2 = 3V / 5

Then,

Ratio of voltage 1 to voltage 2

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V1 : V2 =2 / 3

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The ratio of their voltages is also 2:3

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