Answer:
B. A large cross sectional area,
Explanation:
To permit a large flow of water in a pipe, the cross sectional area of the pipe must be significantly large. According to the flow rate equation:
V =
Where:
Q is the Volume flow rate and it is the volume of fluid that flows through the pipe
V is the velocity of the fluid in the pipe
A is the cross sectional area of the pipe.
From the equation, we see that for a larger amount of water to flow in a pipe, the cross-sectional area must be very large. In short, Q varies directly as A.
M = 40 Kg , g=9.8 m/s² , h = 2 m
PE = m g h
PE = (40) (9.8) (2)
PE = 784 J
KE = PE
½m v² = m g h
½ v² = g h
½ v² = (9.8) (2)
½ v² = 19.6
v² = 19.6×2
v² = 39.2
V = √39.2
V = 6.26 m/s
KE = ½mv²
KE = ½(40) (6.26)²
KE =783.8 J
Answer:
The net force is 392N, pointing down.
Explanation:
The net force is the sum of all forces acting on the rock, namely the gravity ("+" acting downward) and the friction force due to air resistance ("-" acting upward):
The net force is 392N and pointing down (positive)/
Answer:
They have homologous structures because they have a common ancestor.
Explanation: