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Wewaii [24]
1 year ago
14

an object is placed at 19.3 cm in front of a diverging lens with a focal length of -18.7 cm. what is the magnification? enter a

number with 2 digits behind the decimal point.
Physics
1 answer:
Bezzdna [24]1 year ago
8 0

The magnification <u>is 31.16.</u>

Magnification is the process of increasing the apparent size of something rather than its physical size. This increase is quantified by a calculated number, also called the "factor". If this number is less than 1, it means size reduction, sometimes called size reduction or reduction.

u =  -19.3

f = -18.7 cm.

m = f/f-u

    = -18.7/-18.7 +19.3

   <u>= 31.16</u>

The term magnification refers to the size of the image produced by the lens compared to the size of the object. For lenses: Magnification "m" is the ratio of image height to object height. The magnification of a lens is defined as the ratio of image height to object height. It is also given by image distance and object distance. equal to the ratio of image distance to object distance.

Learn more about magnification here:-brainly.com/question/15744335

#SPJ4

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Higher wind speeds would increase the amount of electricity generated by a wind turbine.

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8 0
2 years ago
Suppose a standing wave created on a spring that is 10.5 m long has a speed of 14 m/s and a frequency of 2 Hz. How many nodes an
dimulka [17.4K]

Answer:

If the two waves have the same amplitude and wavelength, then they alternate between ... In fact, the waves are in phase at any integer multiple of half of a period: ... The propagation velocity of the waves is 175 m/s.

Explanation:

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6 0
3 years ago
Determine an appropriate size for a square cross-section solid steel shaft to transmit 260 hp at a speed of 550 rev/min if the m
Phantasy [73]

Answer:46.05 mm

Explanation:

Given

Power=260\ hp\approx 260\times 746=193.96\ KW

speed N=550\ rev/min

allowable shear stress (\tau )_{max}=15\ kpsi\approx 103.421\ MPa

Power is given by

P=\frac{2\pi NT}{60}

193.96=\frac{2\pi 550\times T}{60}

T=3367.6\ N-m

From Torsion Formula

\frac{T}{J}=\frac{\tau }{r}-----1

where J=Polar section modulus

T=Torque

\tau=shear stress

For square cross section

r=\frac{a}{2}

where a=side of square

J=\frac{a^4}{6}

Substituting the values in equation 1

\frac{3376.6}{\frac{a^4}{6}}=\frac{103.421\times 10^6}{\frac{a}{2}}

a=0.04605\ m

a=46.05\ mm

7 0
3 years ago
While working on her science fair project Venus connected a battery to a circuit that contained a light bulb. Venus decided to c
MakcuM [25]
When Venus put in a different battery with higher voltage ... no matter
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7 0
4 years ago
Read 2 more answers
Find the magnitude of the emf induced in the rod when it is moving toward the right with a speed 7.50 m/s.
Flauer [41]

Answer:

3 volts

Explanation:

It is given that,

Magnetic field, B = 0.8 T

Length of a conducting rod, l = 50 cm = 0.5 m

Velocity of the conducting rod, v = 7.5 m/s

We need to find the magnitude of the emf induced in the rod when it is moving toward the right. When a rod is moved in a magnetic field, an emf is induced in it and it is given by :

\epsilon=Blv

Putting all the values,

\epsilon=0.8\times 0.5\times 7.5\\\\\epsilon=3\ V

So, the magnitude of the emf induced in the rod is 3 volts.

6 0
3 years ago
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